我需要将2d整数数组(subSrc)转换为位图.有解决方案吗
private Bitmap decimation(Bitmap src){
Bitmap dest = Bitmap.createBitmap(
src.getWidth(), src.getHeight(), src.getConfig());
int bmWidth = src.getWidth();
int bmHeight = src.getHeight();`enter code here`
int[][] subSrc = new int[bmWidth/2][bmWidth/2];
for(int k = 0; k < bmWidth-2; k++){
for(int l = 0; l < bmHeight-2; l++){
subSrc[k][l] = src.getPixel(2*k, 2*l); <---- ??
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我找了一个接收二维数组(int [] [])的方法并创建了一个Bitmap,但没有找到,所以我自己写了一个:
public static Bitmap bitmapFromArray(int[][] pixels2d){
int width = pixels2d.length;
int height = pixels2d[0].length;
int[] pixels = new int[width * height];
int pixelsIndex = 0;
for (int i = 0; i < width; i++)
{
for (int j = 0; j < height; j++)
{
pixels[pixelsIndex] = pixels2d[i][j];
pixelsIndex ++;
}
}
return Bitmap.createBitmap(pixels, width, height, Bitmap.Config.ARGB_8888);
}
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我还写了一个反向方法:
public static int[][] arrayFromBitmap(Bitmap source){
int width = source.getWidth();
int height = source.getHeight();
int[][] result = new int[width][height];
int[] pixels = new int[width*height];
source.getPixels(pixels, 0, width, 0, 0, width, height);
int pixelsIndex = 0;
for (int i = 0; i < width; i++)
{
for (int j = 0; j < height; j++)
{
result[i][j] = pixels[pixelsIndex];
pixelsIndex++;
}
}
return result;
}
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希望对你有帮助!
您可以使用 setPixel(int, int, int)或setPixels (int[] Pixels, int offset, int stride, int x, int y, int width, int height)方法位图类。
Bitmap dest = Bitmap.createBitmap(
src.getWidth()/2, src.getHeight()/2, src.getConfig());
int bmWidth = src.getWidth();
int bmHeight = src.getHeight();
for(int k = 0; k < bmWidth/2; k++){
for(int l = 0; l < bmHeight/2; l++){
dest.setPixel(k,l,src.getPixel(2*k, 2*l));
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但我认为这会慢一些。
对于第二种方法,你必须这样做
int subSrc = new int[(bmWidth/2*)(bmHeight/2)];
for(int k = 0; k < bmWidth-2; k++){
subSrc[k] = src.getPixel(2*(k/bmWidth), 2*(k%bmHeight)); <---- ??
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