重新排列n列中的文件内容

Question

我有一个内容为:

        000000000000000000000000
00000000000000000000000000000000
0000000000000000000000001f000000
01000000060000000000000034000000
3f000000000000000000000004000000
000000001b0000000900000000000000
00000000600300001000000009000000
010000000400000008000000

我想通过指定col的数量来重新排列其内容.例如,如果我说col的值为80,则输出应该是:

00000000000000000000000000000000000000000000000000000000000000000000000000000000
1f000000010000000600000000000000340000003f00000000000000000000000400000000000000
1b000000090000000000000000000000600300001000000009000000010000000400000008000000

谁能帮我这个 ？xxd可以在这里服务吗？谢谢.

Answer 1

您可以使用tr先从内容中删除空格,然后使用fold它们以特定的线宽包装它们.

cat infile.txt | tr -d "[:space:]" | fold -80