使用jquery和.submit捕获表单提交

Nat*_*han 57 html javascript jquery

我正在尝试使用jQuery捕获提交事件,然后将格式化为JSON的表单元素发送到PHP页面.我在捕获提交时遇到了问题,我从一个.click()事件开始,但转移到了.submit()一个事件.

我现在有以下修剪过的代码.

HTML

<form method="POST" id="login_form">
    <label>Username:</label>
    <input type="text" name="username" id="username"/>
    <label>Password:</label>
    <input type="password" name="password" id="password"/>
    <input type="submit" value="Submit" name="submit" class="submit" id="submit" />
</form>
Run Code Online (Sandbox Code Playgroud)

使用Javascript

$('#login_form').submit(function() {
    var data = $("#login_form :input").serializeArray();
    alert('Handler for .submit() called.');
});
Run Code Online (Sandbox Code Playgroud)

ade*_*neo 145

将文档中的代码包装好,并阻止默认的提交操作:

$(function() { //shorthand document.ready function
    $('#login_form').on('submit', function(e) { //use on if jQuery 1.7+
        e.preventDefault();  //prevent form from submitting
        var data = $("#login_form :input").serializeArray();
        console.log(data); //use the console for debugging, F12 in Chrome, not alerts
    });
});
Run Code Online (Sandbox Code Playgroud)


and*_*lzo 14

试试这个:

使用'return false'来减少事件的流程:

$('#login_form').submit(function() {
    var data = $("#login_form :input").serializeArray();
    alert('Handler for .submit() called.');
    return false;  // <- cancel event
});
Run Code Online (Sandbox Code Playgroud)

编辑

如果表单元素具有jQuery的'length',则证实:

alert($('#login_form').length) // if is == 0, not found form
$('#login_form').submit(function() {
    var data = $("#login_form :input").serializeArray();
    alert('Handler for .submit() called.');
    return false;  // <- cancel event
});
Run Code Online (Sandbox Code Playgroud)

要么:

它等待DOM准备就绪:

jQuery(function() {

    alert($('#login_form').length) // if is == 0, not found form
    $('#login_form').submit(function() {
        var data = $("#login_form :input").serializeArray();
        alert('Handler for .submit() called.');
        return false;  // <- cancel event
    });

});
Run Code Online (Sandbox Code Playgroud)

您是否将代码放入事件"准备好"文档或DOM准备好之后?


cra*_*s84 6

只需将form.submit函数替换为您自己的实现:

var form = document.getElementById('form');
var formSubmit = form.submit; //save reference to original submit function

form.onsubmit = function(e)
{
    formHandler();
    return false;
};

var formHandler = form.submit = function()
{
    alert('hi there');
    formSubmit(); //optionally submit the form
};
Run Code Online (Sandbox Code Playgroud)