cut() - 包括最低值

Question

我想使用以下定义的中断来剪切数据cut():

x = c(-10:10)

cut(x, c(-2,4,6,7))

[1] <NA>   <NA>   <NA>   <NA>   <NA>   <NA>   <NA>   <NA>   <NA>   (-2,4] (-2,4] (-2,4] (-2,4] (-2,4] (-2,4] (4,6]  (4,6]  (6,7]  <NA>   <NA>  
[21] <NA>  
Levels: (-2,4] (4,6] (6,7]

但是,我也想获得水平(minimum:-2]和(7:maximum].在recode()汽车包装的功能中,可以使用"lo:".是否有类似的东西可用于切割？

Answer 1

x <- -10:10

cut(x, c(-Inf, -2, 4, 6, 7, +Inf))

# Levels: (-Inf,-2] (-2,4] (4,6] (6,7] (7, Inf]

Answer 2

您可以使用min()和max()评估间隔范围(如Gavin所述)并设置include.lowest = TRUE为确保最小值(此处为-10)是间隔的一部分.

输入:

x = c(-10:10)

cut(x, c(min(x),-2,4,6,7,max(x)), include.lowest = TRUE)

输出:

 [1] [-10,-2] [-10,-2] [-10,-2] [-10,-2] [-10,-2] [-10,-2] [-10,-2] [-10,-2] [-10,-2] (-2,4]  
[11] (-2,4]   (-2,4]   (-2,4]   (-2,4]   (-2,4]   (4,6]    (4,6]    (6,7]    (7,10]   (7,10]  
[21] (7,10]  
Levels: [-10,-2] (-2,4] (4,6] (6,7] (7,10]

Answer 3

findInterval 就是答案。

i <- findInterval(x, c(-2,4,6,7))

cbind(x, i)

        x i
 [1,] -10 0
 [2,]  -9 0
 [3,]  -8 0
 [4,]  -7 0
 [5,]  -6 0
 [6,]  -5 0
 [7,]  -4 0
 [8,]  -3 0
 [9,]  -2 1
[10,]  -1 1
[11,]   0 1
[12,]   1 1
[13,]   2 1
[14,]   3 1
[15,]   4 2
[16,]   5 2
[17,]   6 3
[18,]   7 4
[19,]   8 4
[20,]   9 4
[21,]  10 4