找到员工的所有主管

Question

我知道答案似乎是根据这篇文章使用"WITH RECURSIVE",但我只是没有得到它.

我有一个叫做的表people,还有一个叫做的表position_hierarchy.该people表具有uperson_id我们调用的唯一ID 和位置ID pcn以及enabled标志(因为当有人离开并被替换时,他们的替换变得相同pcn).在position_hierarchy有柱pcn,以及另一列reports_to这是pcn在层次在他们之上的人.我想要做的是给一个人uperson_id并uperson_id在层次结构中找到他们上面的所有人,和/或给一个uperson_id人和另一个人,uperson_id并告诉第二个人是否具有超过第一个人的监督职位.

公司总裁表示,因为他们pcn和他们一样reports_to.(不是我的决定 - 我会使用null reports_to)

到目前为止我想出的是:

with recursive parents (uperson_id, pcn, reports_to) as
(
 select p1.uperson_id, ph1.pcn, ph1.reports_to
 from people p1
 join position_hierarchy ph1 on ph1.pcn = p1.pcn
 where reports_to != ph1.pcn and active_revoke_flag = '0'

 union all

 select p2.uperson_id, ph2.pcn, ph2.reports_to
 from people p2
 join position_hierarchy ph2 on p2.pcn = ph2.pcn
 join parents pp on pp.pcn = ph2.reports_to
)
select parents.* from parents where uperson_id = 'aaa3644';

但是返回5行,使用相同的uperson_id,pcn和reports_to(这似乎是正确的行数,但我希望每个级别的主管的uperson_id.我觉得我缺少一些非常基本的东西,我可能会打耳光当你告诉我我做错了什么时,我的脑袋.

我做了什么

根据Erwin Brandstetter的回答,我解决了一些问题(主要是因为我没有弄清楚它active_revoke_flag在哪个表格中)并想出了:

with recursive p as (
    select pcn, reports_to
    from   position_hierarchy
    where  pcn = (SELECT pcn FROM people WHERE uperson_id = 'aaa3644')
    union all
    select ph2.pcn, ph2.reports_to
    from   p
    join   position_hierarchy ph2 ON ph2.pcn = p.reports_to AND
           p.pcn != p.reports_to
)
select p2.uperson_id, p2.active_revoke_flag, p.*
from   p
join   people p2 USING (pcn)
where  p2.active_revoke_flag = '0';

Answer 1

我会尝试这种自下而上的方法，从感兴趣的人开始，然后逐步向上：

with recursive p as (
    select p1.uperson_id, p1.pcn, ph1.reports_to
    from   people p1
    join   position_hierarchy ph1 USING (pcn)
    where  ph1.active_revoke_flag = '0'
    and    p1.uperson_id = 'aaa3644'

    union all

    select p2.uperson_id, p2.pcn, ph2.reports_to
    from   p
    join   position_hierarchy ph2 ON ph2.pcn = p.reports_to
                                 AND ph2.active_revoke_flag = '0'
    join   people p2 ON p2.pcn = ph2.pcn
)
select * from p;

或者，更快，因为我们只加入person一次：

with recursive p as (
    select pcn, reports_to
    from   position_hierarchy
    where  active_revoke_flag = '0'
    and    pcn = (SELECT pcn FROM person WHERE uperson_id = 'aaa3644')

    union all

    select ph2.pcn, ph2.reports_to
    from   p
    join   position_hierarchy ph2 ON ph2.pcn = p.reports_to
                                 AND ph2.active_revoke_flag = '0'
)
select p2.uperson_id, p.*
from   p
join   people p2 USING (pcn); -- assuming pcn is unique in table person

顺便说一句：我确实发现你的设计重复pcn有点可疑。