RuntimeError:无法在2秒内关闭实时测试服务器.服务器可能卡住或生成响应缓慢. - Django

Question

我正在使用Django收到此错误

RuntimeError: Failed to shutdown the live test server in 2 seconds. The server might be stuck or generating a slow response.

我想在我的网站上的菜单上运行一个简单的测试.菜单采用手风琴风格(向下滚动到概述菜单下的示例.手风琴是Demo中的东西,根据您点击它们的方式菜单出现和消失:http://docs.jquery.com/UI/手风琴#概述)

当其中一个菜单打开时,会出现一个用于搜索的文本框.我要做的是按下该按钮,然后输入一些值并单击"确定"以查看搜索结果.

码

from django.test import LiveServerTestCase
from selenium.webdriver.firefox.webdriver import WebDriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
import time

class SeleniumTests(LiveServerTestCase):
    fixtures = ['testData.json',]

    @classmethod
    def setUpClass(cls):
        cls.driver = WebDriver()
        super(SeleniumTests, cls).setUpClass()

    @classmethod
    def tearDownClass(cls):
        super(SeleniumTests, cls).tearDownClass()
        cls.driver.quit()

    def test_example(self):

        #load the site 
        self.driver.get('%s%s' % (self.live_server_url, '/testingDB/'))
        #find the accordion button
        elem1 = self.driver.find_element_by_id("search_button")
        #click it
        elem1.click()

        #wait a little bit so the accordion loads 
        self.driver.implicitly_wait(5)
        #could've also used this command ->time.sleep(1)

        #find the element that now appeared
        elem = self.driver.find_element_by_name("q")
        #enter the search query and press enter 
        elem.send_keys("selenium" + Keys.RETURN)
        #assert that a new page loaded, with Search in the title
        assert "Search" in self.driver.title

测试效果很好,但Django给了我错误.如果我把时间缩短太多,那么selenium将无法找到搜索框,它声称

Element is not currently visible and so may not be interacted with

我不知道如何避免实时测试服务器错误.(从https://docs.djangoproject.com/en/dev/topics/testing/#django.test.LiveServerTestCase获得的Django信息)

附加信息

这是菜单:

第1部分

然后单击"搜索",大约0.5秒后出现以下内容.

第2部分

Answer 1

您看到的错误与找到的清理代码相关联SeleniumTests.tearDownClass(cls).在该方法中,如果您在调用cls.driver.quit()之前调用super(SeleniumTests, cls).tearDownClass()错误将消失.