如何将存储库注入Symfony中的服务？

Question

我需要注入两个对象ImageService.其中一个是Repository/ImageRepository我的例子:

$image_repository = $container->get('doctrine.odm.mongodb')
    ->getRepository('MycompanyMainBundle:Image');

那么如何在我的services.yml中声明呢？这是服务:

namespace Mycompany\MainBundle\Service\Image;

use Doctrine\ODM\MongoDB\DocumentRepository;

class ImageManager {
    private $manipulator;
    private $repository;

    public function __construct(ImageManipulatorInterface $manipulator, DocumentRepository $repository) {
        $this->manipulator = $manipulator;
        $this->repository = $repository;
    }

    public function findAll() {
        return $this->repository->findAll();
    }

    public function createThumbnail(ImageInterface $image) {
        return $this->manipulator->resize($image->source(), 300, 200);
    }
}

Answer 1

以下是像我这样来自谷歌的人的清理解决方案:

更新:这是Symfony 2.6(及以上)解决方案:

services:

    myrepository:
        class: Doctrine\ORM\EntityRepository
        factory: ["@doctrine.orm.entity_manager", getRepository]
        arguments:
            - MyBundle\Entity\MyClass

    myservice:
        class: MyBundle\Service\MyService
        arguments:
            - "@myrepository"

不推荐使用的解决方案(Symfony 2.5及更低版本):

services:

    myrepository:
        class: Doctrine\ORM\EntityRepository
        factory_service: doctrine.orm.entity_manager
        factory_method: getRepository
        arguments:
            - MyBundle\Entity\MyClass

    myservice:
        class: MyBundle\Service\MyService
        arguments:
            - "@myrepository"

Answer 2

我找到了这个链接,这对我有用:

parameters:
    image_repository.class:            Mycompany\MainBundle\Repository\ImageRepository
    image_repository.factory_argument: 'MycompanyMainBundle:Image'
    image_manager.class:               Mycompany\MainBundle\Service\Image\ImageManager
    image_manipulator.class:           Mycompany\MainBundle\Service\Image\ImageManipulator

services:
    image_manager:
        class: %image_manager.class%
        arguments:
          - @image_manipulator
          - @image_repository

    image_repository:
        class:           %image_repository.class%
        factory_service: doctrine.odm.mongodb
        factory_method:  getRepository
        arguments:
            - %image_repository.factory_argument%

    image_manipulator:
        class: %image_manipulator.class%

Answer 3

如果不想将每个存储库定义为服务,从2.4可以执行以下操作的版本开始,(default是实体管理器的名称):

@=service('doctrine.orm.default_entity_manager').getRepository('MycompanyMainBundle:Image')

Answer 4

2017年和Symfony 3.3+使这更加简单.在Symfony 4.x中也是如此.

查看我的文章如何在Symfony中将Repository与Doctrine as Service一起使用以获得更多一般性描述.

对于您的代码,您需要做的就是使用组合而不是继承 - 一种SOLID模式.

1.创建自己的存储库,而不直接依赖于Doctrine

<?php

namespace MycompanyMainBundle\Repository;

use Doctrine\ORM\EntityManagerInterface;
use MycompanyMainBundle\Entity\Image;

class ImageRepository
{
    private $repository;

    public function __construct(EntityManagerInterface $entityManager)
    {
        $this->repository = $entityManager->getRepository(Image::class);
    }

    // add desired methods here
    public function findAll()
    {
        return $this->repository->findAll();
    }
}

2.使用基于PSR-4的自动注​​册添加配置注册

# app/config/services.yml
services:
    _defaults:
        autowire: true

    MycompanyMainBundle\:
        resource: ../../src/MycompanyMainBundle

3.现在,您可以通过构造函数注入添加任何依赖项

use MycompanyMainBundle\Repository\ImageRepository;

class ImageService
{
    public function __construct(ImageRepository $imageRepository)
    {
        $this->imageRepository = $imageRepository;
    }
}