尝试在Python中使用带有列表的'pop'方法时出错

Question

我正在尝试编写一个简单的过程,它只保留一个输入列表(包括嵌套列表).

程序本身 -

def is_list(p):
    return isinstance(p, list)

def deep_reverse(input):
    result = []
    if len(input) == 0:
        return []
    for element in input:
        if is_list(element) == True:
            deep_reverse(element)
        else:
            appended = input.pop
            result.append(appended)
            print result
    return result

我正在输入什么来执行程序 -

p = [1, [2, 3, [4, [5, 6]]]]
print deep_reverse(p)
print p

结果 -

[built-in method pop of list object at 0xb752b0cc]
[built-in method pop of list object at 0xb7529c6c]
[built-in method pop of list object at 0xb7529cec]
[built-in method pop of list object at 0xb7529ecc]
[built-in method pop of list object at 0xb7529ecc]
[1, [2, 3, [4, [5, 6]]]]

我究竟做错了什么？

Answer 1

.pop是一种方法.你必须称它为:

appended = input.pop()

这将采取最后一个元素input.如果你想取第一个元素,给它一个参数:

appended = input.pop(0)