Codeigniter,密码或用户名不正确的消息(数据库验证)

Question

问题1)如果用户名和/或密码不正确,我已经设置了注册/登录区域并验证了所有内容(包括空字段)并在显示错误消息时遇到了问题.目前,如果字段留空,我可以收到显示的错误消息,但是在提交页面时,如果用户信息正确或不正确,则会重定向到"私人页面".这是我目前的代码:

问题1(已解决):

控制器:

//This method will have the credentials validation
    public function credentials_validation() {
        $data['error'] ="Invalid Username or Password";
        $this->load->library('form_validation');
        $this->form_validation->set_rules('username', 'Username', 'trim|required|xss_clean|callback_username_check');
        $this->form_validation->set_rules('password', 'Password', 'trim|required|xss_clean|callback_password_check');

          if($this->form_validation->run() == FALSE)
           {
             //Field validation failed.  User redirected to login page
             $this->index();

             }else{
                 $this->load->model('register_model');

                if($query = $this->register_model->validate()) {
                $this->load->model('news_model');

                $data = array('news' => $this->news_model->getArticle());
                $data['title'] = 'Admin | Home';
                $data['heading'] = 'News Articles';
                $data['main_content'] = 'admin/news';
                $this->load->view('include/template', $data);

                }else {
                $this->load->view('login',$data);
                }    

            }
    }

问题2)新闻文章页面只加载1篇文章,网址显示班级名称.

新闻控制器:

class News extends CI_Controller {

    public function __construct() {
        parent::__construct();
        $this->load->model('admin/news_model');
    }

    public function index() {
        $data = array('news' => $this->news_model->getArticle());
        $data['title'] = 'Admin | News Home';
        $data['heading'] = 'News Articles';
        $this->load->view('admin/news', $data); 
}

}

新闻模型只是拉数据库表,选择全部并按ID排序并生成数组.任何人都有任何想法为什么这只显示1个结果？我认为它与foreach方法有关？

PS,CI或php错误日志中没有显示错误消息!

Answer 1

最好的方法是将错误消息存储在数组中,例如

$data['error'] ="Invalid Login";

例如在控制器中

if($query = $this->register_model->check_membership()) {
    $data['main_content'] = 'signup_successful';
    $this->load->view('include/template', $data);

}else {
    $data["error"]="Invalid User Id and Password combination";
    $this->load->view('signup',$data);
}

该check_membership函数应检查登录ID和密码组合是否正常.

然后在signup视图页面中,将一些东西放在顶部

if (isset($error)){
    echo "<div class='error'>$error</div>";
}