$ mysqli-> fetch_object($ result)无效

Question

我正在学习mysqli.

我试图从表"tbllogin"中获取数据.

      //DATABASE CONNECTION

      $hostname="p:localhost";
      $database="dbLogin";
      $username="user1";
      $password="pwd1";



      $mysqli = new mysqli($hostname, $username, $password,$database);

      if(mysqli_connect_errno()){

       echo mysqli_connect_error();

      }

      // Create Query
      $query = "SELECT * FROM tbllogin";


      // Escape Query

      $query = $mysqli->real_escape_string($query);
      echo $query;

      // Execute Query

      if($result = $mysqli->query($query)){

          print_r($result);

          while($row = $mysqli->fetch_object($result)){

              echo $row->column;

          }

          //Free result set
          $result->close();

      }



      ?>

但是$mysqli->fetch_object($result)没有用.if包含的语句$mysqli->fetch_object($result)不执行.我无法确定是否有任何错误.

请帮忙.另外,建议mysqli程序形式是更好还是面向对象形式？

提前致谢.

Answer 1

不应该$result->fetch_object()吗？

http://php.net/manual/en/mysqli-result.fetch-object.php

从例1:

if ($result = $mysqli->query($query)) {

    /* fetch object array */
    while ($obj = $result->fetch_object()) {
        printf ("%s (%s)\n", $obj->Name, $obj->CountryCode);
    }

根据此stackoverflow页面上的答案,两者之间没有太大区别.