t0x*_*x13 8 python timezone datetime epoch
在下面的代码中,我正在计算现在的纪元和当天纪元的开始.
import time
import pytz
from datetime import datetime
tz1 = pytz.timezone('CST6CDT')
utc = pytz.timezone('UTC')
now = pytz.UTC.localize(datetime.utcnow())
now_tz = now.astimezone(tz1)
print now_tz
print now_tz.strftime('%s')
begin_day = now_tz.replace(hour=0, minute=0, second=0)
print begin_day
print begin_day.strftime('%s')
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打印声明:
2012-08-28 13:52:21.595718-05:00
1346187141
2012-08-28 00:00:00.595718-05:00
1346137200
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使用CDT时区将时期转换为时间戳:1346187141 - 2012年8月28日15:52:21,1346137200 - 2012年8月28日02:00:00
我希望第二个时代开始,但现在是凌晨2点.在转换为纪元时,它看起来仍然使用本地时区PST.
我究竟做错了什么 ?或者这可以用不同的方式完成吗?
谢谢!
jfs*_*jfs 26
要将带有时区的日期时间转换为纪元(POSIX时间戳):
from datetime import datetime
import pytz
tz = pytz.timezone('CST6CDT')
# a datetime with timezone
dt_with_tz = tz.localize(datetime(2012, 8, 28, 19, 33, 50), is_dst=None)
# get timestamp
ts = (dt_with_tz - datetime(1970, 1, 1, tzinfo=pytz.utc)).total_seconds()
# -> 1346200430.0
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这是在Python 3中为时datetime.timestamp区感知datetime对象实现方法的方法.
获得"现在的时代":
from datetime import datetime
now_epoch = (datetime.utcnow() - datetime(1970, 1, 1)).total_seconds()
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或者(假设time使用POSIX纪元):
import time
now_epoch = time.time()
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获取"当前时代的开始"更为复杂,因为当前日期在不同的时区可能会有所不同:
from datetime import datetime, time
import pytz
tz = pytz.timezone('CST6CDT')
# get current date in given timezone
today = datetime.now(tz).date()
# -> datetime.date(2013, 6, 22)
# get beginning of current day in given timezone as a datetime with timezone
midnight = tz.localize(datetime.combine(today, time(0, 0)), is_dst=None)
# -> datetime.datetime(2013, 6, 22, 0, 0, tzinfo=<DstTzInfo 'CST6CDT'...>)
# get timestamp
ts = (midnight - datetime(1970, 1, 1, tzinfo=pytz.utc)).total_seconds()
# -> 1371877200.0
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假设UTC日期为"获得当天纪元的开始":
from datetime import datetime, date
# get current date in UTC
utc_date = datetime.utcnow().date()
# -> datetime.date(2013, 6, 23)
# get timestamp
ts = (utc_date - date(1970, 1, 1)).days * 86400
# -> 1371945600
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请参阅在Python中将datetime.date/datetime.datetime转换为UTC时间戳.
注意:我的答案是错误的.(我想删除它,但是在删除accept标志之前我无法删除它.)
请参阅JFSebastian的回答.
下面的代码演示了now_tz我们的两种方法产生不同结果的值.
import calendar
import pytz
import datetime as dt
tz1 = pytz.timezone('US/Eastern')
utc = pytz.timezone('UTC')
now = utc.localize(dt.datetime(2002, 10, 28), is_dst=None)
now_tz = now.astimezone(tz1)
now_epoch = calendar.timegm(now_tz.utctimetuple())
begin_day = tz1.normalize(now_tz.replace(hour=0, minute=0, second=0))
midnight = tz1.localize(dt.datetime.combine(now_tz, dt.time(0, 0)), is_dst=None)
if begin_day != midnight:
print(begin_day)
# 2002-10-27 01:00:00-04:00 # my result -- is not midnight
print(midnight)
# 2002-10-27 00:00:00-04:00 # J.F.Sebastian's result is correct
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(原始答案编辑)
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