如何消除“丢弃限定符”警告？

Question

使用 GCC 和 C99 模式，我有一个函数声明为：

void func(float *X);

当我调用该函数时，我使用了一个可变数组 Y：

volatile float Y[2];
int main()
{
    func(Y);
    return 0;
}

When compiling (with -Wall), I get the following warning:

warning: passing argument 1 of ‘func’ discards qualifiers from pointer target type
blah.c:4: note: expected ‘float *’ but argument is of type ‘volatile float *’

I can eliminate it with an explicit (float *) type cast, but this repeats in many places in the code.

Is there a way to eliminate this specific warning, with an option or a pragma (or something equivalent)?

Answer 1

不，您无法关闭该警告。它告诉你你违反了类型系统。如果您想调用，func则需要向其传递指向非易失性数据的指针，或者更改函数签名以接受指向易失性数据的指针。