Seb*_*ber 18 java serialization json gson
我有一个具有以下属性的对象.
private final String messageBundle;
private final List<String> messageParams;
private final String actionBundle;
private final Map<String, String> data;
private final Optional<Pair<Integer,TimeUnit>> ttl;
private final Optional<Integer> badgeNumber;
private final Optional<String> collapseKey;
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该对象位于库中,我宁愿不仅仅为了序列化目的而修改它,并且希望避免创建另一个DTO的成本.
如何序列化/反序列化可选属性?可选没有默认构造函数(apache commons Pair),但是我不能使用InstanceCreator,并且不太了解如何创建一个简单地将序列化委托给底层Optional元素的TypeAdapter.
小智 18
经过几个小时的gooling和编码 - 有我的版本:
public class OptionalTypeAdapter<E> extends TypeAdapter<Optional<E>> {
public static final TypeAdapterFactory FACTORY = new TypeAdapterFactory() {
@Override
public <T> TypeAdapter<T> create(Gson gson, TypeToken<T> type) {
Class<T> rawType = (Class<T>) type.getRawType();
if (rawType != Optional.class) {
return null;
}
final ParameterizedType parameterizedType = (ParameterizedType) type.getType();
final Type actualType = parameterizedType.getActualTypeArguments()[0];
final TypeAdapter<?> adapter = gson.getAdapter(TypeToken.get(actualType));
return new OptionalTypeAdapter(adapter);
}
};
private final TypeAdapter<E> adapter;
public OptionalTypeAdapter(TypeAdapter<E> adapter) {
this.adapter = adapter;
}
@Override
public void write(JsonWriter out, Optional<E> value) throws IOException {
if(value.isPresent()){
adapter.write(out, value.get());
} else {
out.nullValue();
}
}
@Override
public Optional<E> read(JsonReader in) throws IOException {
final JsonToken peek = in.peek();
if(peek != JsonToken.NULL){
return Optional.ofNullable(adapter.read(in));
}
return Optional.empty();
}
}
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您可以GsonBuilder
像这样简单地注册它:
instance.registerTypeAdapterFactory(OptionalTypeAdapter.FACTORY)
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请注意,如果json中没有字段,Gson不会为您的类字段设置值.因此,您需要Optional.empty()
在实体中设置默认值.
Ilya的解决方案忽略了类型参数,因此在一般情况下它无法真正起作用.我的解决方案相当复杂,因为需要区分null
和Optional.absent()
- 否则你可以将封装剥离为列表.
public class GsonOptionalDeserializer<T>
implements JsonSerializer<Optional<T>>, JsonDeserializer<Optional<T>> {
@Override
public Optional<T> deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context)
throws JsonParseException {
final JsonArray asJsonArray = json.getAsJsonArray();
final JsonElement jsonElement = asJsonArray.get(0);
final T value = context.deserialize(jsonElement, ((ParameterizedType) typeOfT).getActualTypeArguments()[0]);
return Optional.fromNullable(value);
}
@Override
public JsonElement serialize(Optional<T> src, Type typeOfSrc, JsonSerializationContext context) {
final JsonElement element = context.serialize(src.orNull());
final JsonArray result = new JsonArray();
result.add(element);
return result;
}
}
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