Yas*_*tha 0 html php arrays while-loop
我有一个数据库表,该表有6行.我想要的是使用3列和2行表在html页面中显示6行.
我知道如何使用php数组和while循环.我的问题是如何限制数组在第一行放置3个项目,并将另外3个项目放在下一行.
这是我尝试但没有奏效的
<div id="maincontent">
<!-- class one -->
<?php
$getSection = getSection();
$i=0;
while($allSection = mysql_fetch_array($getSection)){
?>
<div class="subconent">
<table width="937" border="0">
<tr>
<td>
<div class="sub_image">
<a href="section.php?id=<?php echo urlencode($allSection['id']); ?>"><img src="admin/uploads/fron_sect/<?php echo $allSection['image']; ?>" width="134" height="120" border="0" alt="HNA" class="PopBoxImageLink" onmouseover="PopEx(this,-50,-25,205,186,20,null);" onclick="window.location='http://localhost/hants/section.php?id=<?php echo urlencode($allSection['id']); ?>'" /></a>
</div>
<div class="cont_txt">
<h3><?php echo $allSection['name_full']; ?></h3>
<p><?php echo substr($allSection['description'],0,140) . ""; ?></p>
<br />
<a href="section.php?id=<?php echo urlencode($allSection['id']); $i++; ?>"><img src="images/read_more.jpg" alt="Read More" width="89" height="25" border="0" /></a>
</div>
</td>
</tr>
</table>
</div>
<?php
if($i==4) { ?>
<table width="937" border="0">
<tr>
<td> </td>
<td> </td>
<td> </td></tr>
<tr><div class="sub_image">
<a href="section.php?id=<?php echo urlencode($allSection['id']); ?>"><img src="admin/uploads/fron_sect/<?php echo $allSection['image']; ?>" width="134" height="120" border="0" alt="HNA" class="PopBoxImageLink" onmouseover="PopEx(this,-50,-25,205,186,20,null);" onclick="window.location='http://localhost/hants/section.php?id=<?php echo urlencode($allSection['id']); ?>'" /></a>
</div>
<div class="cont_txt">
<h3><?php echo $allSection['name_full']; ?></h3>
<p><?php echo substr($allSection['description'],0,140) . ""; ?></p>
<br />
<a href="section.php?id=<?php echo urlencode($allSection['id']); ?>"><img src="images/read_more.jpg" alt="Read More" width="89" height="25" border="0" /></a>
</div><td>
<?php }
} ?>
</div>
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使用模运算符(%):
http://www.devchunks.com/web-development/using-the-php-modulus-operator/
这样的事情:
<table>
<?php
$i = 0;
while ( $row = mysql_fetch_array($result) ){
if ($i % 3 == 0){
echo '<tr>';
}
echo '<td>'.$row['column_name'].'</td>';
if ($i % 3 == 2){
echo '</tr>';
}
$i++;
}
//here is a check in case you don't have multiple of 3 rows
if ($i % 3 != 0){
echo '</tr>';
}
?>
</table>
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