Abi*_*n K 20
(我的回答有点迟到了.但我希望它对未来的访问者有用)
下图中给出了非恢复除法的算法:

在这个问题中,Dividend(A)= 101110,即46,Divisor(B)= 010111,即23.
初始化:
Set Register A = Dividend = 000000
Set Register Q = Dividend = 101110
( So AQ = 000000 101110 , Q0 = LSB of Q = 0 )
Set M = Divisor = 010111, M' = 2's complement of M = 101001
Set Count = 6, since 6 digits operation is being done here.
Run Code Online (Sandbox Code Playgroud)
在此之后我们启动算法,我已在下表中显示:
在表中,SHL(AQ) denotes shift left AQ by one position leaving Q0 blank.
同样,Q0位置的方形符号表示, it is to be calculated later

希望从表中清楚所有步骤!