为什么不打印此例外？为什么会出现错误？

Question

如果我试图打印"a"的值,为什么显示错误？为什么异常会成为错误？

class Ankit1
{
    public static void main(String args[])
    {
        float d,a;
        try
        {
            d=0;
            a=44/d;
            System.out.print("It's not gonna print: "+a); // if exception doesn't occur then it will print and it will go on to the catch block
        }
        catch (ArithmeticException e)
        {
            System.out.println("a:" + a); // why is this an error??
        }
    }
}

Answer 1

如果你看到错误

Exception in thread "main" java.lang.Error: Unresolved compilation problem: 
    The local variable a may not have been initialized

    at your.package.Ankit1.main(Ankit1.java:18)

这清楚地说明了 The local variable a may not have been initialized

由于您的变量a未初始化,因此收到此错误.

如果要打印错误消息,请尝试打印... e.getMessage()或p.printStackTrace()完整的堆栈跟踪.

要修复这个简单的初始化a,有这样的值......

float a = 0;