Bfa*_*ace 9 foreach for-loop xtend
我似乎无法找到一种在Xtend中表达以下内容的好方法,而不需要使用while循环:
for(int i = 0; i < 3; i++){
println("row ");
}
println("your boat");
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所以,我猜我的问题有两个部分:
我最终滚动自己,得到如下内容:
class LanguageUtil {
def static Iterable<Integer> range(int stop) {
range(0, stop)
}
def static Iterable<Integer> range(int start, int stop) {
new RangeIterable(start, stop, 1)
}
def static Iterable<Integer> range(int start, int stop, int step) {
new RangeIterable(start, stop, step)
}
}
// implements Iterator and Iterable which is bad form.
class RangeIterable implements Iterator<Integer>, Iterable<Integer> {
val int start
val int stop
val int step
var int current
new(int start, int stop, int step) {
this.start = start;
this.stop = stop;
this.step = step
this.current = start
}
override hasNext() {
current < stop
}
override next() {
val ret = current
current = current + step
ret
}
override remove() {
throw new UnsupportedOperationException("Auto-generated function stub")
}
/**
* This is bad form. We could return a
* new RangeIterable here, but that seems worse.
*/
override iterator() {
this
}
}
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rzy*_*mek 17
确切的替代品
for(int i = 0; i < 3; i++){
println("row ");
}
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是
for (i : 0 ..< 3) {
println("row ")
}
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注意独家范围运算符: ..<
Del*_*ney 14
你也可以用惯用语来做
(1..3).forEach[println("row")]
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对于Xtend来说很新,但是它让它在jvm上编程非常棒.
对我来说,基于范围forEach意味着范围在某种程度上是有意义的.为了在没有迭代变量的情况下循环特定次数,我发现Ruby的times循环更清楚地表达了意图:
3.times [|println("row")]
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可悲的是,它不是其中的一部分IntegerExtensions,但实施是微不足道的:
def static times(int iterations, Runnable runnable) {
if (iterations < 0) throw new IllegalArgumentException(
'''Can't iterate negative («iterations») times.''')
for (i: 0 ..< iterations) runnable.run()
}
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