Raj*_*eev 0 android android-emulator android-intent android-layout
在下面的代码点击按钮我想隐藏相对布局rl1和显示rl2但我的应用程序在按钮点击后崩溃.我做错了什么
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="wrap_content"
>
<RelativeLayout
android:id="@+id/rl1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@drawable/welcome_1">
<ImageView
android:id="@+id/button1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentRight="true"
android:paddingTop="360dp"
android:layout_marginRight="4dp"
android:src="@drawable/button1" />
</RelativeLayout>
<RelativeLayout
android:id="@+id/rl2"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:visibility="invisible"
android:background="@drawable/menu_2"
></RelativeLayout>
</RelativeLayout>
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Java代码
public class mockupsActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// ImageButton img1 = (ImageButton)findViewById(R.id.button1);
ImageView img1 =(ImageView)findViewById(R.id.button1);
img1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// your code here
// Toast.makeText(TouchpointmockupsActivity.this, "test", Toast.LENGTH_SHORT).show();
LinearLayout rl1 = (LinearLayout) findViewById(R.id.rl1);
rl1.setVisibility(View.INVISIBLE);
LinearLayout rl2 = (LinearLayout) findViewById(R.id.rl2);
rl2.setVisibility(View.VISIBLE);
}
});
}
}
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更改LinearLayout 为RelativeLayout您的代码.您可能会收到classcastException.
编辑:更改OnClick方法如下
RelativeLayout rl1 = (RelativeLayout) findViewById(R.id.rl1);
rl1.setVisibility(View.INVISIBLE);
RelativeLayout rl2 = (RelativeLayout) findViewById(R.id.rl2);
rl2.setVisibility(View.VISIBLE);
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