onActivityResult中的操作和"错误无法在onSaveInstanceState之后执行此操作"

Question

实现用户可以登录的应用程序我有以下情况:如果用户已登录,则执行操作,否则启动结果的登录活动,如果结果是Activity.RESULT_OK,则执行操作.

我的问题是,要执行的操作是显示DialogFragment,但是调用

DialogFragment newFragment = MyDialogFragment.newInstance(mStackLevel);
newFragment.show(ft, "dialog")

在onActivityResult回调中引发异常:

Caused by: java.lang.IllegalStateException:  
Can not perform this action after onSaveInstanceState

那我怎么解决这个问题呢？我正在考虑在那里举起一个标志并在onResume中显示对话框,但我看到这个解决方案有点脏

编辑:添加了更多代码(我按照此示例显示DialogFragment

当用户请求操作时:

... 
if (!user.isLogged()){
 startActivityForResult(new Intent(cnt, Login.class), REQUEST_LOGIN_FOR_COMMENT);
}

在同一个片段中

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == REQUEST_LOGIN_FOR_COMMENT && resultCode == Activity.RESULT_OK) {
        FragmentTransaction ft = getFragmentManager().beginTransaction();
        DialogFragment newFragment = MyDialogFragment.newInstance();
        newFragment.show(ft, "dialog")
    }
}

如果用户登录Login活动调用;

setResult(Activity.RESULT_OK);
finish();

Answer 1

我想出的最好的事情是不要使用.show()而是这样做.

CheckinSuccessDialog dialog = new CheckinSuccessDialog();
//dialog.show(getSupportFragmentManager(), null);
FragmentTransaction ft = getSupportFragmentManager().beginTransaction();
ft.add(dialog, null);
ft.commitAllowingStateLoss();

Answer 2

这是适合我的解决方法.

private void alert(final String message) {
    Handler handler = new Handler(Looper.getMainLooper());
    handler.post(new Runnable() {
        public void run() {
            AlertDialogFragment alertDialogFragment = AlertDialogFragment.newInstance(message);
            alertDialogFragment.show(getFragmentManager(), ALERT_DIALOG_FRAGMENT);
        }
    });        
}