如何在Python中生成唯一ID？

Question

我需要根据随机值生成唯一ID.

Answer 1

也许uuid.uuid4()可以做这个工作.有关更多信息,请参阅uuid.

Answer 2

您可能需要Python的UUID功能:

21.15.uuid - 根据RFC 4122的UUID对象

例如:

import uuid
print uuid.uuid4()

7d529dd4-548b-4258-aa8e-23e34dc8d43d

Answer 3

独特和随机是相互排斥的.也许你想要这个？

import random
def uniqueid():
    seed = random.getrandbits(32)
    while True:
       yield seed
       seed += 1

用法:

unique_sequence = uniqueid()
id1 = next(unique_sequence)
id2 = next(unique_sequence)
id3 = next(unique_sequence)
ids = list(itertools.islice(unique_sequence, 1000))

没有两个返回的id是相同的(唯一),这是基于随机种子值

Answer 4

import time
import random
import socket
import hashlib

def guid( *args ):
    """
    Generates a universally unique ID.
    Any arguments only create more randomness.
    """
    t = long( time.time() * 1000 )
    r = long( random.random()*100000000000000000L )
    try:
        a = socket.gethostbyname( socket.gethostname() )
    except:
        # if we can't get a network address, just imagine one
        a = random.random()*100000000000000000L
    data = str(t)+' '+str(r)+' '+str(a)+' '+str(args)
    data = hashlib.md5(data).hexdigest()

    return data

Answer 5

也许这对你有用

str(uuid.uuid4().fields[-1])[:5]