php PDO插入不起作用,没有错误

Question

我有这种代码的和平,应该将记录插入到mysql数据库中:

$sql = "INSERT INTO connections (column1, column2, column3, column4, column5, column6, column7) VALUES (?, ?, ?, ?, ?, ?, ?)')";
$stmt = $pdo->prepare($sql);
if (!$stmt) {
    echo "\nPDO::errorInfo():\n";
    print_r($pdo->errorInfo());
}
$stmt->execute(array('wer','wer','wer','2','wer','wer','wer'));

我没有收到任何错误,并且记录未显示在表格中.怎么可能出错？

更新:

由于以下答案,这是完整的工作代码:

$sql = "INSERT INTO connections (column1, column2, column3, column4, column5, column6, column7) VALUES (?, ?, ?, ?, ?, ?, ?)";
$stmt = $pdo->prepare($sql);
if (!$stmt) {
    echo "\nPDO::errorInfo():\n";
    print_r($pdo->errorInfo());
}
$stmt->execute(array('wer','wer','wer','2','wer','wer','wer'));

Answer 1

SQL命令末尾有语法错误.删除额外的').它应该是:

$sql = "INSERT INTO connections (column1, column2, column3, column4, column5, column6, column7) 
        VALUES (?, ?, ?, ?, ?, ?, ?)";

代替

$sql = "INSERT INTO connections (column1, column2, column3, column4, column5, column6, column7) 
        VALUES (?, ?, ?, ?, ?, ?, ?)')";
                                    ^^--- error here