C#:如何以编程方式检查Web服务是否已启动并正在运行？

Question

我需要创建一个C#应用程序,它将监视一组Web服务是否已启动并正在运行.用户将从下拉列表中选择服务名称.该程序需要使用相应的服务URL进行测试,并显示该服务是否正在运行.最好的方法是什么？我想到的一种方法是测试我们是否能够下载wsdl.有没有更好的办法？

注意:此应用程序的目的是用户只需要知道服务名称.他不需要记住/存储服务的相应URL.

我需要一个网站版本和这个C#应用程序的桌面应用程序版本.

注意:现有服务正在使用WCF.但是将来可能会添加非WCF服务.

注意:我的程序不会知道(或不感兴趣)服务中的操作.所以我无法调用服务操作.

参考

1. 如何在不使用ping的情况下检查Web服务是否已启动并运行？
2. C程序 - 如何检查Web服务是否正在运行

Answer 1

这不保证功能,但至少你可以检查到URL的连接:

var url = "http://url.to.che.ck/serviceEndpoint.svc";

try
{
    var myRequest = (HttpWebRequest)WebRequest.Create(url);

    var response = (HttpWebResponse)myRequest.GetResponse();

    if (response.StatusCode == HttpStatusCode.OK)
    {
        //  it's at least in some way responsive
        //  but may be internally broken
        //  as you could find out if you called one of the methods for real
        Debug.Write(string.Format("{0} Available", url));
    }
    else
    {
        //  well, at least it returned...
        Debug.Write(string.Format("{0} Returned, but with status: {1}", 
            url, response.StatusDescription));
    }
}
catch (Exception ex)
{
    //  not available at all, for some reason
    Debug.Write(string.Format("{0} unavailable: {1}", url, ex.Message));
}

Answer 2

I may be too late with the answer but this approach works for me. I used Socket to check if the process can connect. HttpWebRequest works if you try to check the connection 1-3 times but if you have a process which will run 24hours and from time to time needs to check the webserver availability that will not work anymore because will throw TimeOut Exception.

Socket socket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
                var result = socket.BeginConnect("xxx.com", 80, null, null);
                bool success = result.AsyncWaitHandle.WaitOne(3000,false); // test the connection for 3 seconds
                var resturnVal = socket.Connected;
                if (socket.Connected)
                    socket.Disconnect(true);
                socket.Dispose();
                return resturnVal;