Lor*_*ard 28 javascript jquery post jasmine
这是关于javascript提交请求的代码(1).
以下是使用jasmine(2)模拟ajax请求的测试.
我想模拟服务器行为.有任何想法吗?
有关详细信息,请参阅(1)和(2)中的注释.
PS:
实际上在两种情况下都会调用fakeFunction的done和fail Deferred Object.
(1)
submitForm: function () {
// the server execute fail only if message.val() is empty
// and I would like to mock this behaviour in (2)
backendController.submitForm(message.val()).done(this.onSuccess).fail(this.onError);
},
backendController.submitForm = function (message) {
return $.ajax({
url: 'some url',
type: 'POST',
dataType: 'json',
data: {
message: message
}
}).done(function () {
//some code;
});
};
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(2)
describe('When Submit button handler fired', function () {
var submitFormSpy,
fakeFunction = function () {
this.done = function () {
return this;
};
this.fail = function () {
return this;
};
return this;
};
beforeEach(function () {
submitFormSpy = spyOn(backendController, 'submitForm').andCallFake(fakeFunction);
});
describe('if the message is empty', function () {
beforeEach(function () {
this.view.$el.find('#message').text('');
this.view.$el.find('form').submit();
});
it('backendController.submitForm and fail Deferred Object should be called', function () {
expect(submitFormSpy).toHaveBeenCalled();
// how should I test that fail Deferred Object is called?
});
});
describe('if the message is not empty', function () {
beforeEach(function () {
this.view.$el.find('#message').text('some text');
this.view.$el.find('form').submit();
});
it('backendController.submitForm should be called and the fail Deferred Object should be not called', function () {
expect(submitFormSpy).toHaveBeenCalled();
// how should I test that fail Deferred Object is not called?
});
});
});
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Ain*_*aer 25
我们实际上遇到了同样的问题,试图测试代表AJAXed模板脚本的Deferred对象以进行实时模板化.我们的测试解决方案涉及将Jasmine-Ajax库与Jasmine本身结合使用.
所以可能会是这样的:
describe('When Submit button handler fired', function () {
jasmine.Ajax.useMock();
describe('if the message is empty', function () {
beforeEach(function() {
spyOn(backendController, 'submitForm').andCallThrough();
// replace with wherever your callbacks are defined
spyOn(this, 'onSuccess');
spyOn(this, 'onFailure');
this.view.$el.find('#message').text('');
this.view.$el.find('form').submit();
});
it('backendController.submitForm and fail Deferred Object should be called', function () {
expect(backendController.submitForm).toHaveBeenCalledWith('');
mostRecentAjaxRequest().response({
status: 500, // or whatever response code you want
responseText: ''
});
expect( this.onSuccess ).not.toHaveBeenCalled();
expect( this.onFailure ).toHaveBeenCalled();
});
});
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另一件事,如果可以的话,尝试分解功能,这样你就不会在一次测试中测试整个DOM-to-response-callback路径.如果你足够精细,你可以通过在测试中使用Deferred对象来实际测试异步延迟分辨率!
关键是在测试中实际使用Deferred对象,这样expect
调用的范围仍然在你的it
功能块中.
describe('loadTemplate', function() {
it('passes back the response text', function() {
jasmine.Ajax.mock();
loadTemplate('template-request').done(function(response) {
expect(response).toBe('foobar');
});
mostRecentAjaxRequest().response({ status:200, responseText:'foobar' });
});
});
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Ton*_*ony 14
以下是我设法做到的方法.
本质上,$ .ajax对象返回一个Deferred对象,因此您可以监视$ .ajax并返回Deferred,然后手动触发它以在JavaScript中运行.done()代码
码
Index.prototype.sendPositions = function() {
var me = this;
$.ajax({
...
}).done(function(data, textStatus, jqXHR) {
me.reload();
}).fail(function(jqXHR, textStatus, errorThrown) {
console.log(errorThrown);
});
};
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测试
it("should reload the page after a successful ajax call", function(){
var deferred = new jQuery.Deferred();
spyOn($, 'ajax').andReturn(deferred);
spyOn(indexPage, 'reload');
indexPage.sendPositions();
deferred.resolve('test');
expect(indexPage.reload).toHaveBeenCalled();
});
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