我无耻地从这个问题中扯下了这个例子,并将它从C#转换为VB.net.
Public Function GetNthIndex(s As String, t As Char, n As Integer) As Integer
Dim count As Integer = 0
For i As Integer = 0 To s.Length - 1
If s(i) = t Then
count += 1
If count = n Then
Return i
End If
End If
Next
Return -1
End Function
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这是Linq的一种方法.
Public Function GetNthIndex(searchString As String, charToFind As Char, n As Integer) As Integer
Dim charIndexPair = searchString.Select(Function(c,i) new with {.Character = c, .Index = i}) _
.Where(Function(x) x.Character = charToFind) _
.ElementAtOrDefault(n-1)
Return If(charIndexPair IsNot Nothing, charIndexPair.Index, -1)
End Function
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用法:
Dim searchString As String = "Assessment"
Dim index As Integer = GetNthIndex(searchString, "s", 4) 'Returns 5
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