可能重复:
如何使用linq扩展方法执行左外连接
我找不到Linq lambda的左外连接示例(使用扩展方法),至少不是一个明确的.
假设我有下表:
Parent
{
PID // PK
}
Child
{
CID // PK
PID // FK
Text
}
Run Code Online (Sandbox Code Playgroud)
我想加入Parent with Child,对于每个失踪的孩子,我希望Text的默认值为"[[Empty]]".我怎么能用linq lambda语法做到这一点?
我目前有以下内容:
var source = lParent.GroupJoin(
lChild,
p => p.PID,
c => c.PID,
(p, g) =>
new // ParentChildJoined
{
PID = p.PID;
// How do I add child values here?
});
Run Code Online (Sandbox Code Playgroud)
Raw*_*ing 75
你很亲密 下面将选择PID,CID并Text为每一个孩子,和PID,CID = -1和Text = "[[Empty]]"为没有孩子每个父母:
var source = lParent.GroupJoin(
lChild,
p => p.PID,
c => c.PID,
(p, g) => g
.Select(c => new { PID = p.PID, CID = c.CID, Text = c.Text })
.DefaultIfEmpty(new { PID = p.PID, CID = -1, Text = "[[Empty]]" }))
.SelectMany(g => g);
Run Code Online (Sandbox Code Playgroud)
from p in Parent
join c in Child on p.PID equals c.PID into g
from c in g.DefaultIfEmpty
select new
{
p.PID,
CID = c != null ? (int?)c.CID : null, // Could be null
Text = c != null ? c.Text : "[[Empty]]"
}
Run Code Online (Sandbox Code Playgroud)
使用lambda:
class ChildResult
{
public int PID { get; set; }
public int? CID { get; set; }
public string Text { get; set; }
}
lParent.SelectMany(p => p.Childs.Any() ?
p.Childs.Select(c => new ChildResult() { PID = c.PID, CID = c.CID, Text = c.Text }) :
new [] { new ChildResult() { PID = p.PID, CID = null, Text = "[[Empty]]" } } );
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
54716 次 |
| 最近记录: |