使用Naudio将每个WAV通道保存为单通道WAV文件

Question

我正在尝试将WAV文件(PCM,48kHz,4通道,16位)转换为单通道WAV文件.

我尝试将WAV文件拆分成4个字节数组,就像这个答案一样,并创建了一个WaveMemoryStream,如下所示,但不起作用.

byte[] chan1ByteArray = new byte[channel1Buffer.Length];
Buffer.BlockCopy(channel1Buffer, 0, chan1ByteArray, 0, chan1ByteArray.Length);
WaveMemoryStream chan1 = new WaveMemoryStream(chan1ByteArray, sampleRate, (ushort)bitsPerSample, 1);

我在创建WAVE标题时遗漏了什么？或者更多的是将WAV分成单声道WAV文件？

Answer 1

基本思想是源波文件包含交错的样本.一个用于第一个通道,一个用于第二个通道,依此类推.这里有一些未经测试的示例代码,可以让您了解如何执行此操作.

var reader = new WaveFileReader("fourchannel.wav");
var buffer = new byte[2 * reader.WaveFormat.SampleRate * reader.WaveFormat.Channels];
var writers = new WaveFileWriter[reader.WaveFormat.Channels];
for (int n = 0; n < writers.Length; n++) 
{
    var format = new WaveFormat(reader.WaveFormat.SampleRate,16,1);
    writers[n] = new WaveFileWriter(String.Format("channel{0}.wav",n+1), format);
}
int bytesRead;
while((bytesRead = reader.Read(buffer,0, buffer.Length)) > 0) 
{
    int offset=  0;
    while (offset < bytesRead) 
    {
        for (int n = 0; n < writers.Length; n++) 
        {
            // write one sample
            writers[n].Write(buffer,offset,2);
            offset += 2;
        }           
    }
}
for (int n = 0; n < writers.Length; n++) 
{
    writers[n].Dispose();
}
reader.Dispose();