Mar*_*ers 33
只需从给定日期减去一天,然后检查日期是否为工作日.如果没有,减去另一个,直到你有一个工作日:
from datetime import date, timedelta
def prev_weekday(adate):
adate -= timedelta(days=1)
while adate.weekday() > 4: # Mon-Fri are 0-4
adate -= timedelta(days=1)
return adate
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演示:
>>> prev_weekday(date.today())
datetime.date(2012, 8, 20)
>>> prev_weekday(date(2012, 8, 20))
datetime.date(2012, 8, 17)
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或者,使用偏移表; 没有必要使这个映射,一个元组将做得很好:
_offsets = (3, 1, 1, 1, 1, 1, 2)
def prev_weekday(adate):
return adate - timedelta(days=_offsets[adate.weekday()])
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