Zde*_*end 8 spring specifications jpa criteria-api spring-data-jpa
我有使用Spring数据JPA规范从实体Person获取List的问题(因为分页).我需要逐个获得所有笔记,但这两个实体之间的依赖关系是在人员方面.我不知道如何创建我的谓词因为Note不包含任何与Person相关的属性.
我只能得到List with Persons getter但我不能用这种方式,因为我需要返回数据分页.
@Entity
public class Person implements Serializable {
@Id
private Long personId;
@OneToMany
@JoinColumn(name = "personId")
private List<Note> notes;
}
@Entity
public class Note implements Serializable {
@Id
private Long noteId;
}
Run Code Online (Sandbox Code Playgroud)
通常情况下,我会写这样的东西,但我没有注释中的属性人,数据库在此阶段无法重新映射.
public static Specification<Note> notesByPerson(final Long personId) {
return new Specification<Note>() {
@Override
public Predicate toPredicate(final Root<Note> root, final CriteriaQuery<?> query,
final CriteriaBuilder builder) {
final Path<Person> per = root.<Person> get("person");
return builder.equal(per.<Long> get("personId"), personId);
}
};
}
Run Code Online (Sandbox Code Playgroud)
谢谢你,Zdend
Zde*_*end 12
解决了..
public static Specification<Note> notesByPerson(final Long personId) {
return new Specification<Note>() {
@Override
public Predicate toPredicate(final Root<Note> noteRoot, final CriteriaQuery<?> query,
final CriteriaBuilder cb) {
final Subquery<Long> personQuery = query.subquery(Long.class);
final Root<Person> person = personQuery.from(Person.class);
final Join<Person, Note> notes = person.join("notes");
personQuery.select(notes.<Long> get("noteId"));
personQuery.where(cb.equal(person.<Long> get("personId"), personId));
return cb.in(noteRoot.get("noteId")).value(personQuery);
}
};
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
16839 次 |
| 最近记录: |