自动分离已经相乘的两个图像

Nic*_*nar 7 c++ matlab image image-processing

我正在寻找一种算法或C++/Matlab库,可用于将两个图像相乘.下面给出了该问题的可视示例.

图像1可以是任何东西(例如相对复杂的场景).图像2非常简单,可以在数学上生成.图像2总是具有相似的形态(即下降趋势).通过将图像1乘以图像2(使用逐点乘法),我们得到变换后的图像.

给出转换后的图像,我想估计图像1或图像2.是否有算法可以做到这一点?

这是Matlab代码和图像:

load('trans.mat');
imageA = imread('room.jpg');
imageB = abs(response);  % loaded from MAT file

[m,n] = size(imageA);
image1 = rgb2gray( imresize(im2double(imageA), [m n]) );
image2 = imresize(im2double(imageB), [m n]);

figure; imagesc(image1); colormap gray; title('Image 1 of Room')
colorbar

figure; imagesc(image2); colormap gray; title('Image 2 of Response')
colorbar

% This is image1 and image2 multiplied together (point-by-point)
trans = image1 .* image2;
figure; imagesc(trans); colormap gray; title('Transformed Image')
colorbar
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图片1 图2 转化后的形象

UPDATE

有很多方法可以解决这个问题.以下是我的实验结果.感谢所有回答我问题的人!

1.图像的低通滤波

如duskwuff所述,采用变换图像的低通滤波器返回图像2的近似值.在这种情况下,低通滤波器是高斯滤波器.您可以看到可以使用低通滤波器识别图像中的乘法噪声.

原始图像 高斯低通滤波图像

2.同态过滤

正如EitenT所建议的,我研究了同态滤波.知道了这种类型的图像过滤的名称,我设法找到了一些我认为在解决类似问题时有用的参考文献.

  1. SP Bank,信号处理,图像处理和模式识别.纽约:普伦蒂斯霍尔,1990年.

  2. A.Oppenheim,R.Schafer和J.Stockham,T.,"非线性滤波乘法和卷积信号",IEEE Transactions on Audio and Electroacoustics,vol.16,不.3,pp.437-466,1968年9月.

  3. 盲图解卷积:理论和应用.博卡拉顿:CRC出版社,2007年.

Blind图像解卷积书的第5章特别好,并且包含许多对同态滤波的参考.这可能是最通用的方法,可以在许多不同的应用程序中很好地工作.

3.优化使用 fminsearch

正如Serg所建议的那样,我使用了一个目标函数fminsearch.由于我知道噪声的数学模型,我能够将其用作优化算法的输入. 这种方法完全针对特定问题,在所有情况下可能并不总是有用.

这是图2的重建:

重建图像

这是图像1的重建,通过除以图像2的重建形成:

图片1

这是包含噪音的图像:

包含噪音的图像

源代码

这是我的问题的源代码.如代码所示,这是一个非常具体的应用程序,并不适用于所有情况.

N = 1001;
q = zeros(N, 1);
q(1:200) = 55;
q(201:300) = 120;
q(301:400) = 70;
q(401:600) = 40;
q(601:800) = 100;
q(801:1001) = 70;
dt = 0.0042;
fs = 1 / dt;
wSize = 101;
Glim = 20;
ginv = 0;
[R, ~, ~] = get_response(N, q, dt, wSize, Glim, ginv);
rows = wSize;
cols = N;
cut_val = 200;

figure; imagesc(abs(R)); title('Matrix output of algorithm')
colorbar

figure;
imagesc(abs(R)); title('abs(response)')

figure;
imagesc(imag(R)); title('imag(response)')

imageA = imread('room.jpg');

% images should be of the same size
[m,n] = size(R);
image1 =  rgb2gray( imresize(im2double(imageA), [m n]) );


% here is the multiplication (with the image in complex space)
trans = ((image1.*1i)) .* (R(end:-1:1, :));


figure;
imagesc(abs(trans)); colormap(gray);


% take the imaginary part of the response
imagLogR = imag(log(trans)); 


% The beginning and end points are not usable
Mderiv = zeros(rows, cols-2);
for k = 1:rows
   val = deriv_3pt(imagLogR(k,:), dt);
   val(val > cut_val) = 0;
   Mderiv(k,:) = val(1:end-1);
end


% This is the derivative of the imaginary part of R
% d/dtau(imag((log(R)))
% Do we need to remove spurious values from the matrix?
figure; 
imagesc(abs(log(Mderiv)));


disp('Running iteration');
% Apply curve-fitting to get back the values
% by cycling over the cols
q0 = 10;
q1 = 500;
NN = cols - 2;
qout = zeros(NN, 1);
for k = 1:NN
    data = Mderiv(:,k); 
    qout(k) = fminbnd(@(q) curve_fit_to_get_q(q, dt, rows, data),q0,q1);
end


figure; plot(q); title('q value input as vector'); 
ylim([0 200]); xlim([0 1001])

figure;
plot(qout); title('Reconstructed q')
ylim([0 200]); xlim([0 1001])

% make the vector the same size as the other
qout2 = [qout(1); qout; qout(end)];

% get the reconstructed response
[RR, ~, ~] = get_response(N, qout2, dt, wSize, Glim, ginv);
RR = RR(end:-1:1,:);

figure; imagesc(abs(RR)); colormap gray 
title('Reconstructed Image 2')
colorbar; 

% here is the reconstructed image of the room
% NOTE the division in the imagesc function
check0 = image1 .* abs(R(end:-1:1, :));
figure; imagesc(check0./abs(RR)); colormap gray
title('Reconstructed Image 1')
colorbar; 

figure; imagesc(check0); colormap gray
title('Original image with noise pattern')
colorbar; 

function [response, L, inte] = get_response(N, Q, dt, wSize, Glim, ginv)

fs = 1 / dt; 
Npad = wSize - 1; 
N1 = wSize + Npad;
N2 = floor(N1 / 2 + 1);
f = (fs/2)*linspace(0,1,N2);
omega = 2 * pi .* f';
omegah = 2 * pi * f(end);
sigma2 = exp(-(0.23*Glim + 1.63));

sign = 1;
if(ginv == 1)
    sign = -1;
end

ratio = omega ./ omegah;
rs_r = zeros(N2, 1);  
rs_i = zeros(N2, 1);   
termr = zeros(N2, 1);
termi = zeros(N2, 1);
termr_sub1 = zeros(N2, 1);
termi_sub1 = zeros(N2, 1);
response = zeros(N2, N);
L = zeros(N2, N);
inte = zeros(N2, N);

 % cycle over cols of matrix
for ti = 1:N               

    term0 = omega ./ (2 .* Q(ti));
    gamma = 1 / (pi * Q(ti));

    % calculate for the real part
    if(ti == 1)
        Lambda = ones(N2, 1);
        termr_sub1(1) = 0;  
        termr_sub1(2:end) = term0(2:end) .* (ratio(2:end).^-gamma);  
    else
        termr(1) = 0; 
        termr(2:end) = term0(2:end) .* (ratio(2:end).^-gamma); 
        rs_r = rs_r - dt.*(termr + termr_sub1);
        termr_sub1 = termr;
        Beta = exp( -1 .* -0.5 .* rs_r );

        Lambda = (Beta + sigma2) ./ (Beta.^2 + sigma2);  % vector
    end 

    % calculate for the complex part  
    if(ginv == 1)  
        termi(1) = 0;
        termi(2:end) = (ratio(2:end).^(sign .* gamma) - 1) .* omega(2:end);
    else
        termi = (ratio.^(sign .* gamma) - 1) .* omega;
    end
    rs_i = rs_i - dt.*(termi + termi_sub1);
    termi_sub1 = termi;
    integrand = exp( 1i .* -0.5 .* rs_i );

    L(:,ti) = Lambda;
    inte(:,ti) = integrand;

    if(ginv == 1) 
        response(:,ti) = Lambda .* integrand;
    else        
        response(:,ti) = (1 ./ Lambda) .* integrand;
    end  
end % ti loop

function sse = curve_fit_to_get_q(q, dt, rows, data)

% q = trial q value
% dt = timestep
% rows = number of rows
% data = actual dataset

fs = 1 / dt;
N2 = rows;
f = (fs/2)*linspace(0,1,N2);  % vector for frequency along cols
omega = 2 * pi .* f';
omegah = 2 * pi * f(end);
ratio = omega ./ omegah;

gamma = 1 / (pi * q);

% calculate for the complex part  
termi = ((ratio.^(gamma)) - 1) .* omega;

% for now, just reverse termi 
termi = termi(end:-1:1);
% 

% Do non-linear curve-fitting

% termi is a column-vector with the generated noise pattern 
% data is the log-transformed image
% sse is the value that is returned to fminsearchbnd
Error_Vector =  termi - data;
sse = sum(Error_Vector.^2);

function output = deriv_3pt(x, dt)

N = length(x);
N0 = N - 1;
output = zeros(N0, 1);
denom = 2 * dt;

for k = 2:N0 
   output(k - 1) = (x(k+1) - x(k-1)) / denom;  
end
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dus*_*uff 5

这将是一个困难,不可靠的过程,因为你从根本上试图提取已被破坏的信息(两个图像的分离).把它完美地带回来是不可能的; 你能做的最好的就是猜测.

如果第二个图像总是相对"平滑",则可以通过对变换后的图像应用强低通滤波器来重建它(或者至少是它的近似值).有了这个,您可以反转乘法,或等效地使用互补高通滤波器来获得第一个图像.它不会完全相同,但它至少会成为一种东西.


Ser*_*erg 3

我会尝试约束优化(fmincon在Matlab中)。如果您了解第二张图像的来源/性质,您可能可以定义一个生成类似噪声模式的多元函数。目标函数可以是生成的噪声图像与最后图像之间的相关性。