在python中加入一个字符串列表,并用引号将每个字符串包装起来

Question

我有:

words = ['hello', 'world', 'you', 'look', 'nice']

我希望有:

'"hello", "world", "you", "look", "nice"'

使用Python最简单的方法是什么？

Answer 1

>>> words = ['hello', 'world', 'you', 'look', 'nice']
>>> ', '.join('"{0}"'.format(w) for w in words)
'"hello", "world", "you", "look", "nice"'

Answer 2

你也可以进行一次format通话

>>> words = ['hello', 'world', 'you', 'look', 'nice']
>>> '"{0}"'.format('", "'.join(words))
'"hello", "world", "you", "look", "nice"'

更新:一些基准测试(在2009 mbp上执行):

>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.32559704780578613

>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; '"{}"'.format('", "'.join(words))""").timeit(1000)
0.018904924392700195

所以看起来format实际上相当昂贵

更新2:关注@JCode的评论,添加一个map以确保它join能够正常工作,Python 2.7.12

>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.08646488189697266

>>> timeit.Timer("""words = ['hello', 'world', 'you', 'look', 'nice'] * 100; '"{}"'.format('", "'.join(map(str, words)))""").timeit(1000)
0.04855608940124512

>>> timeit.Timer("""words = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] * 100; ', '.join('"{0}"'.format(w) for w in words)""").timeit(1000)
0.17348504066467285

>>> timeit.Timer("""words = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] * 100; '"{}"'.format('", "'.join(map(str, words)))""").timeit(1000)
0.06372308731079102

Answer 3

你可以试试这个:

str(words)[1:-1]

Answer 4

>>> ', '.join(['"%s"' % w for w in words])

Answer 5

@jamylak 答案的更新版本，带有 F 字符串（适用于 python 3.6+），我对用于 SQL 脚本的字符串使用了反引号。

keys = ['foo', 'bar' , 'omg']
', '.join(f'`{k}`' for k in keys)
# result: '`foo`, `bar`, `omg`'