从Java中的String数组中删除未填充的值或空值

Question

我tmp = [null, null, null, Mars, Saturn, Mars]在执行操作后会跟随String Array - allSig[d3].split(" ");其中allSig是一个字符串数组.null值是数组中的空值.现在我想删除null.为此,我正在使用

tmp[indexNumber] != null是不工作和给予真实; 取null作为值.即使我使用"null"作为字符串不起作用.

如何删除它.

public static String[] removeElements(String[] allElements) {
    String[] _localAllElements = new String[allElements.length];

    for (int i = 0; i < allElements.length; i++)
        if (allElements[i] != null)
            _localAllElements[i] = allElements[i];

    return _localAllElements;
}

Answer 1

最简单的解决方案

 public static String[] clean(final String[] v) {
    List<String> list = new ArrayList<String>(Arrays.asList(v));
    list.removeAll(Collections.singleton(null));
    return list.toArray(new String[list.size()]);
}

Answer 2

public static String[] clean(final String[] v) {
  int r, w;
  final int n = r = w = v.length;
  while (r > 0) {
    final String s = v[--r];
    if (!s.equals("null")) {
      v[--w] = s;
    }
  }
  return Arrays.copyOfRange(v, w, n);
}

或者

public static String[] clean(final String[] v) {
  int r, w, n = r = w = v.length;
  while (r > 0) {
    final String s = v[--r];
    if (!s.equals("null")) {
      v[--w] = s;
    }
  }
  final String[] c = new String[n -= w];
  System.arraycopy(v, w, c, 0, n);
  return c;
}

工作正常...

public static void main(final String[] argv) {
  final String[] source = new String[] { "Mars", "null", "Saturn", "null", "Mars" };
  assert Arrays.equals(clean(source), new String[] { "Mars", "Saturn", "Mars" });
}