C++期望在"int"之前的primary-expression

Ang*_*gie 3 c++ dev-c++

本周的家庭作业分配是创建一个基本的c ++程序,要求用户输入以英尺和英寸为单位的长度,然后以厘米为单位输出; 我们要创建一个异常并让它处理它,如果用户输入一个负数或一个字符.我有代码写,但当它编译时,我得到错误:

在函数'int main()'中:在第19行的"int"之前的"int"期望')之前的期望的primary-expression.

这是我的代码:

#include <iostream>

using namespace std;

const double centimetersPerInch = 2.54; //named constant
const int inchesPerFoot = 12; //named constant

int main ()
{
    int feet;
    int inches; //declared variables    
    int totalInches;
    double centimeters;
    //statements
cout << "Enter two integers one for feet and " << "one for inches: ";
cin >> feet >> inches;
try
{
     if ( int feet, int inches < 0.0 )
        throw "Please provide a positive number";
cout << endl;

cout << "The numbers you entered are " << feet << " for feet and " << inches << " for inches. " << endl;               
    totalInches = inchesPerFoot * feet + inches;     

cout << "The total number of inches = " << totalInches << endl;                   
    centimeters = centimetersPerInch * totalInches;

cout << "The number of centimeters = " << centimeters << endl;   
}
catch (char* strException)
{
      cerr << "Error: " << strException << endl;
}

    return 0;
}
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我认为这是一个简单的事情,我忽略了但我无法弄清楚我的问题是什么.任何帮助深表感谢.提前致谢.

jog*_*pan 8

if ( int feet, int inches < 0.0 )
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你可以隐式重新声明之前声明过的两个整数变量.你不应该这样做.相反,只需使用它们:

if (feet, inches < 0.0 )
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现在,这可能不是你的意思.你可能想说这样的话:

if (feet < 0.0 || inches < 0.0 )
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  • @LuchianGrigore除了它意味着另一件事:))))) (5认同)
  • `if(feet,inches <0.0)`完全有效. (3认同)