luk*_*012 5 sql t-sql sql-server-2008
我有一个简单的表,有一些虚拟数据设置,如:
|id|user|value|
---------------
1 John 2
2 Ted 1
3 John 4
4 Ted 2
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我可以通过执行以下sql(MSSQL 2008)语句来选择运行总计:
SELECT a.id, a.user, a.value, SUM(b.value) AS total
FROM table a INNER JOIN table b
ON a.id >= b.id
AND a.user = b.user
GROUP BY a.id, a.user, a.value
ORDER BY a.id
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这会给我的结果如下:
|id|user|value|total|
---------------------
1 John 2 2
3 John 4 6
2 Ted 1 1
4 Ted 2 3
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现在是否可以只检索每个用户的最新行?结果将是:
|id|user|value|total|
---------------------
3 John 4 6
4 Ted 2 3
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我是以正确的方式来做这件事的吗?任何建议或新的路径都会很棒!
不需要加入,您可以通过以下方式加快查询速度:
select id, [user], value, total
from
(
select id, [user], value,
row_number() over (partition by [user] order by id desc) rn,
sum(value) over (partition by [user]) total
from users
) a
where rn = 1
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试试这个:
;with cte as
(SELECT a.id, a.[user], a.value, SUM(b.value) AS total
FROM users a INNER JOIN users b
ON a.id >= b.id
AND a.[user] = b.[user]
GROUP BY a.id, a.[user], a.value
),
cte1 as (select *,ROW_NUMBER() over (partition by [user]
order by total desc) as row_num
from cte)
select id,[user],value,total from cte1 where row_num=1
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