zik*_*y90 34 android android-fragments fragmentpageradapter
我有以下问题:我有一个活动,其中我有两个选项卡,使用FragmentPagerAdapter作为片段 在某些时刻我想更改其中一个片段的视图,但我无法找到FragmentById()或findFragmentByTag( )我无法设置id,因为我没有在XML中声明Fragment,因为FragmentPagerAdapter 当我尝试设置标记时,我遇到了以下问题:
08-15 21:46:23.805: E/AndroidRuntime(9297): java.lang.IllegalStateException: Can't change tag of fragment Companies{416d7b78 id=0x7f04002e companies}: was companies now android:switcher:2130968622:1
Run Code Online (Sandbox Code Playgroud)
我的寻呼机FragmentPagerAdapter的代码:
public class TabsAdapter extends FragmentPagerAdapter implements ActionBar.TabListener, ViewPager.OnPageChangeListener {
private final FragmentActivity mContext;
private final ActionBar mActionBar;
private final ViewPager mViewPager;
private final ArrayList<TabInfo> mTabs = new ArrayList<TabInfo>();
final class TabInfo {
private final Class<?> clss;
private final Bundle args;
TabInfo(Class<?> _class, Bundle _args) {
clss = _class;
args = _args;
}
}
public TabsAdapter(SherlockFragmentActivity activity, ViewPager pager) {
super(activity.getSupportFragmentManager());
mContext = activity;
mActionBar = activity.getSupportActionBar();
mViewPager = pager;
mViewPager.setAdapter(this);
mViewPager.setOnPageChangeListener(this);
}
public void addTab(ActionBar.Tab tab, Class<?> clss, Bundle args) {
TabInfo info = new TabInfo(clss, args);
tab.setTag(info);
tab.setTabListener(this);
mTabs.add(info);
mActionBar.addTab(tab);
notifyDataSetChanged();
}
@Override
public int getCount() {
return mTabs.size();
}
@Override
public Fragment getItem(int position) {
TabInfo info = mTabs.get(position);
FragmentTransaction ft=mContext.getSupportFragmentManager().beginTransaction();
Fragment fragment=Fragment.instantiate(mContext, info.clss.getName(), info.args);
if(position==1){
ft.add(mViewPager.getId(), fragment, "companies");
}else{
ft.add(mViewPager.getId(), fragment);
}
Log.v("FRAGMENT ID", "fragment tag: "+fragment.getTag());
ft.commit();
Log.v("FRAGMENT ID", "fragment tag: "+fragment.getTag());
return fragment;
}
@Override
public void onPageScrolled(int position, float positionOffset, int positionOffsetPixels) {
}
@Override
public void onPageSelected(int position) {
mActionBar.setSelectedNavigationItem(position);
new Thread(new Runnable() {
@Override
public void run() {
MainActivity.this.hideKeyboard();
}
}).start();
}
@Override
public void onPageScrollStateChanged(int state) {
}
@Override
public void onTabSelected(Tab tab, FragmentTransaction ft) {
Object tag = tab.getTag();
for (int i = 0; i < mTabs.size(); i++) {
if (mTabs.get(i) == tag) {
mViewPager.setCurrentItem(i);
}
}
}
@Override
public void onTabUnselected(Tab tab, FragmentTransaction ft) {
}
@Override
public void onTabReselected(Tab tab, FragmentTransaction ft) {
}
}
Run Code Online (Sandbox Code Playgroud)
提前感谢您的回答.
Dee*_*eeV 51
FragmentPagerAdapter提供的Fragments在实例化时会自动标记.您可以使用以下方法检索标记:
private static String makeFragmentName(int viewPagerId, int index) {
return "android:switcher:" + viewPagerId + ":" + index;
}
Run Code Online (Sandbox Code Playgroud)
Dan*_*eón 22
使用此功能,您可以通过寻呼机适配器位置找到片段.
public Fragment findFragmentByPosition(int position) {
FragmentPagerAdapter fragmentPagerAdapter = getFragmentPagerAdapter();
return getSupportFragmentManager().findFragmentByTag(
"android:switcher:" + getViewPager().getId() + ":"
+ fragmentPagerAdapter.getItemId(position));
}
Run Code Online (Sandbox Code Playgroud)
v4支持api的示例代码.
小智 6
我找到了一个稍微不那么粗略的方法来处理由a Fragment创建的句柄FragmentPagerAdapter.不要模仿标签的创建方式,而是覆盖instantiateItem(),获取Fragment超类返回的内容,并保存标签TabInfo.这适用于我在API> = 15,可能工作较低.这仍然会对私有代码做出一些假设.
static final class TabInfo {
private final Class<?> clss;
private final Bundle args;
private String tag; // ** add this
TabInfo(Class<?> _class, Bundle _args) {
clss = _class;
args = _args;
}
}
@Override
public Object instantiateItem(ViewGroup container, int position) {
final Fragment fragment = (Fragment) super.instantiateItem(container, position);
final TabInfo info = mTabs.get(position);
info.tag = fragment.getTag(); // set it here
return fragment;
}
Run Code Online (Sandbox Code Playgroud)
或者在API <16中,我认为instantiateItem()需要View()代替ViewGroup(),而不是像这样:
public Object instantiateItem(View container, int position);
Run Code Online (Sandbox Code Playgroud)
然后允许一种方法获得Fragment,保持黑客包含.
public Fragment getFragment(int index) {
return mContext.getFragmentManager().findFragmentByTag(mTabs.get(index).tag);
}
Run Code Online (Sandbox Code Playgroud)
为了工作,mContext需要改变的声明Activity,它Activity仍然作为一个传递:
private final Activity mContext;
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
40678 次 |
| 最近记录: |