从httppost响应中解析xml

Ted*_*Ted 7 java xml post android http

在执行http POST期间,我将响应存储为String响应.

HttpResponse httpresponse = httpclient.execute(httppost);
HttpEntity resEntity = httpresponse.getEntity();
response = EntityUtils.toString(resEntity);
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如果我打印响应,它看起来像:

<?xml version="1.0" encoding="UTF-8"?>
<response status="ok">
<sessionID>lo8mdn7bientr71b5kn1kote90</sessionID>
</response>
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我想将sessionID存储为字符串.我试过了

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
InputSource is = new InputSource(new StringReader(xml));
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和这样的各种方法,但它不会让我运行代码,因为DocumentBuildFactory和InputSource是无效的.

我应该怎么做才能从这个XML中提取特定的字符串?

su-*_*su- 9

这只是快速而肮脏的测试.它对我有用.

import java.io.IOException;
import java.io.StringReader;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;

import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

public class Test {
    public static void main(String[] args) {
        String xml= "<?xml version=\"1.0\" encoding=\"UTF-8\"?><response status=\"ok\"><sessionID>lo8mdn7bientr71b5kn1kote90</sessionID></response>";
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder;
        InputSource is;
        try {
            builder = factory.newDocumentBuilder();
            is = new InputSource(new StringReader(xml));
            Document doc = builder.parse(is);
            NodeList list = doc.getElementsByTagName("sessionID");
            System.out.println(list.item(0).getTextContent());
        } catch (ParserConfigurationException e) {
        } catch (SAXException e) {
        } catch (IOException e) {
        }
    }
}
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输出:lo8mdn7bientr71b5kn1kote90