Junit mockito when(..).thenReturn()抛出NullPointerException

use*_*577 7 java junit unit-testing mockito

任何人都可以解释我下面的场景
代码测试
UserTransaction.java

@Override
public ServiceResponse<User> get(String name) {
    ServiceResponse<User> response = new ServiceResponse<User>();
    List<Map<String, Object>> exp = new ArrayList<Map<String, Object>>();
    Map<String, Object> map = new HashMap<String, Object>();
    map.put("expression", "eq");
    map.put("property", "name");
    map.put("value", name);
    exp.add(map);
    List<User> users = userDao.getByCriteria(exp);
    if (!users.isEmpty()) {
        response.setResponse(users.get(0));
    } else {
        response.setResponse(null);
    }
    return response;
}   
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UserDao.java

public List<User> getByCriteria(List<Map<String, Object>> exp) {
  DetachedCriteria criteria = DetachedCriteria.forClass(User.class);
  for (Integer i=0;i<exp.size();i++){
    String expression = (String) exp.get(i).get("expression");
    String property = (String) exp.get(i).get("property");
    if(expression.equals("eq"){
       criteria.add(Restrictions.eq(property,exp.get(i).get("value")));
    }
  }
  return hibernateTemplate.findByCriteria(criteria);
 }
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UserTransactionTest.java

private UserTransaction userTransactions = new UserTransaction();
private UserDao userDao = mock(UserDao.class);

@Test
public void testGet() {
   User user = new User();
   user.setName("Raman");
    try {
        when(userDao.getByCriteria(anyList())).thenReturn(user);
    } catch (Exception e) {
        e.printStackTrace();
    }
    ServiceResponse<User> response = userTransactions.get("raman");
    User result = response.getResponse();
    assertEquals("Raman", result.getName());
    assertEquals(0, response.getErrors().size());
}
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工作良好.

但是我没有通过"anyList()"来传递用户定义的列表"myList"

List<Map<String,Object>> myList = new ArrayList<Map<String,Object>>();
Map<String,Object> map = new HashMap<String,Object>();
map.put("expression","eq");
map.put("property","name");
map.put("value","raman");
myList.add(map);
when(userTransactions.getByCriteria(myList)).thenReturn(user);
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投掷NullPointerException线assertEquals().为什么?如果anyList()给出了实际发生的事情?

Tar*_*rek 5

我相信你现在已经解决了你的问题,但如果有人遇到同样的问题,这就是答案:

在您提供的代码中,您没有使用myList您创建的模拟.该get()方法始终调用userDao.getByCriteria(exp)一个局部变量.

这就是为什么anyList()有效,而myList不是.

如果你想测试的表达,List<Map<String,Object>> exp应该是你的类,而不是一个局部变量的成员:

public class UserTransaction {
    private List<Map<String,Object>> exp;

    public UserTransaction() {
        // creating a default exp value
        Map<String, Object> map = new HashMap<String, Object>();
        map.put("expression", "eq");
        map.put("property", "name");
        map.put("value", name);
        exp.add(map);
    }

    // getters and setters for exp

    public ServiceResponse<User> get(String name) {
        ServiceResponse<User> response = new ServiceResponse<User>();
        List<User> users = userDao.getByCriteria(exp);
        if (!users.isEmpty()) {
            response.setResponse(users.get(0));
        } else {
            response.setResponse(null);
        }
        return response;
    }
}
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在你的测试中:

private UserTransaction userTransactions = new UserTransaction();
private UserDao userDao = mock(UserDao.class);

@Test
public void testGet() {
    User user = new User();
    user.setName("Raman");

    // creating a custom expression
    List<Map<String,Object>> myList = new ArrayList<Map<String,Object>>();
    Map<String,Object> map = new HashMap<String,Object>();
    map.put("expression","eq");
    map.put("property","name");
    map.put("value","raman");
    myList.add(map);

    // replacing exp with the list created
    userTransactions.setExp(myList);
    // return user when calling getByCriteria(myList)
    when(userDao.getByCriteria(myList)).thenReturn(user);

    ServiceResponse<User> response = userTransactions.get("raman");
    User result = response.getResponse();
    assertEquals("Raman", result.getName());
    assertEquals(0, response.getErrors().size());
}
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小智 0

我认为 anyList() 是一种您正在嘲笑的方法,而 list 不是一种方法,您能否发布您正在编写此测试用例的任何内容的源代码

  • anyList() 是 Mockito 中的匹配器方法。 (2认同)