从Windows上的proc_open()捕获stderr输出

Question

我正在调用proc_open(),我无法捕获写入stderr的进程的输出:

$curFolder = getcwd();
$procDescriptor = array( 2 => array( "pipe", "w" ) );
$cmd = "MyApp.exe -f optimization.csv";
$process = proc_open( $cmd, $procDescriptor, $pipes, $curFolder );

if( is_resource( $process ) == true ) 
{
  $procStatus = proc_get_status( $process );

  while( $procStatus['running'] === true )
  {
    if( !feof( $pipes[2] ) )
    {
      $logLine = fgets( $pipes[2] );
      echo( "Read >${logLine}<" );
    }
    sleep( 1 );
  }
}

该程序挂起在fgets()上.如果我从命令行运行程序,一切正常,即有一些东西写入stderr(我也试过使用stdout得到相同的结果).我在Windows上运行脚本 - Linux上的相同脚本运行顺利.

Answer 1

你有一个无限循环.

$ procStatus ["运行"]永远不会改变,除非你把电话给proc_get_status()内循环.PHP没有像JavaScript这样的动态属性.

我添加了这条线

$procStatus = proc_get_status( $process );

睡觉后(),它工作正常.

Answer 2

来自proc_open() 文档：

<?php
$descriptorspec = array(
   0 => array("pipe", "r"),  // stdin is a pipe that the child will read from
   1 => array("pipe", "w"),  // stdout is a pipe that the child will write to
   2 => array("file", "/tmp/error-output.txt", "a") // stderr is a file to write to
);

$cwd = '/tmp';
$env = array('some_option' => 'aeiou');

$process = proc_open('php', $descriptorspec, $pipes, $cwd, $env);

if (is_resource($process)) {
    // $pipes now looks like this:
    // 0 => writeable handle connected to child stdin
    // 1 => readable handle connected to child stdout
    // Any error output will be appended to /tmp/error-output.txt

    fwrite($pipes[0], '<?php print_r($_ENV); ?>');
    fclose($pipes[0]);

    echo stream_get_contents($pipes[1]);
    fclose($pipes[1]);

    // It is important that you close any pipes before calling
    // proc_close in order to avoid a deadlock
    $return_value = proc_close($process);

    echo "command returned $return_value\n";
}
?>

如果您发现它是空的，也许您的进程不会向 stderr 报告