如何用tweepy打印完整的URL？

Question

如何在tweepy中打印完整的URL(而不是t.co链接)？以下代码打印出"这是一个测试链接http://t.co/93Hme7Jv 90210",即使twitter.com显示"这是一个测试链接http://www.test.com/test 90210".

import tweepy, random

consumer_key="my_key"
consumer_secret="my_secret"
access_token="my_access"
access_token_secret="my_token"

rand = random.randint(1,999999999)

if __name__ == '__main__':
    auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
    auth.set_access_token(access_token, access_token_secret)
    status = tweepy.API(auth)
    tweepy.API(auth).update_status('this is a test link http://www.test.com/test %s' % (rand))
    user = 'test_user'
    for status in tweepy.Cursor(status.user_timeline, id=user).items(20): 
        print status.text

Answer 1

不确定如何使用tweepy,但是你想设置include_entities为True,Twitter API将包含t.co带响应的URL 的完整URL .

可能是这样的:

for status in tweepy.Cursor(status.user_timeline, id=user, include_entities=True).items(20): 
    for url in status.entities['urls']:
         print url['expanded_url']