add*_*ons 8 python intersection set
我没有意识到Python设置函数实际上将字符串分成单个字符.我为Jaccard编写了python函数并使用了python intersection方法.我将两个集合传递给了这个方法,在将两个集合传递给我的jaccard函数之前,我在setring上使用了set函数.
例如:假设我有字符串NEW Fujifilm 16MP 5x Optical Zoom Point and Shoot CAMERA 2 7 screen.jpg我将调用set(NEW Fujifilm 16MP 5x Optical Zoom Point and Shoot CAMERA 2 7 screen.jpg),它将字符串分成字符.所以当我把它发送到jaccard函数交集时实际看字符交集而不是字对话.我该如何进行单词到单词的交集.
#implementing jaccard
def jaccard(a, b):
c = a.intersection(b)
return float(len(c)) / (len(a) + len(b) - len(c))
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如果我不在set我的字符串上调用函数,我NEW Fujifilm 16MP 5x Optical Zoom Point and Shoot CAMERA 2 7 screen.jpg会收到以下错误:
c = a.intersection(b)
AttributeError: 'str' object has no attribute 'intersection'
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而不是字符到字符的交集我想做单词到单词交叉并获得jaccard相似性.
尝试首先将字符串拆分为单词:
word_set = set(your_string.split())
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例:
>>> word_set = set("NEW Fujifilm 16MP 5x".split())
>>> character_set = set("NEW Fujifilm 16MP 5x")
>>> word_set
set(['NEW', '16MP', '5x', 'Fujifilm'])
>>> character_set
set([' ', 'f', 'E', 'F', 'i', 'M', 'j', 'm', 'l', 'N', '1', 'P', 'u', 'x', 'W', '6', '5'])
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小智 7
我计算Jaccard距离的函数:
def DistJaccard(str1, str2):
str1 = set(str1.split())
str2 = set(str2.split())
return float(len(str1 & str2)) / len(str1 | str2)
>>> DistJaccard("hola amigo", "chao amigo")
0.333333333333
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