在jquery中使用变量代替id名称

Question

我希望使用一个i在for循环中递增的变量来在mako模板中的div中创建唯一的id.

var i=0;
    % for p in row.photos: 
    %if not p.PRIVATE:              
    /* setup div's for photo containers*/

    $('#photos').append("<div id='+i+' class='thumbnailimage'></div>"); 
    $('#+i+').append("<div id='+i+container' class='thumb_container'></div>");  
    $('#+i+container').append("<div id='+i+thumb' class='large_thumb'></div>");
    $('#+i+thumb').append("<div class='large_thumb_border'></div>");
    $('#+i+thumb').append("<div class='large_thumb_shine'></div>");

    /*insert the image*/
    $(document.createElement("img")).attr({ "src": "${tg.url('photo/%s/%s' % (p.PHOTOINDEX))}" }).appendTo('#+i+'thumb'');

    i++;


    %endif
% endfor

运行javascript时希望在html中的结果:

<div id='photos'>
    <div id='1'class='thumbnailimage'>
        <div id='1container' class='thumb_container'> 

等我得到:

<div id='photos'>
    <div id='+1+' class...>
    </div>
</div><!--end photos-->        

有什么建议？

根据以下建议,我将代码更改为

$('#photos').append("<div id="'photo'+i+" class='thumbnailimage'></div>"); 
$("#'photo'+i+").append("<div id="'container'+i+" class='thumb_container'></div>");  
$("#'container'+i+").append("<div id="'thumb'+i+" class='large_thumb'></div>");
$("#'thumb'+i+").append("<div class='large_thumb_border'></div>");
$("#'thumb'+i+").append("<div class='large_thumb_shine'></div>");

现在我在参数列表后出现错误消息:SyntaxError:missing)[Break On This Error]

$('#photos').append("<div id="photo+i+" class='thumbnailimage'></div>");

在照片中的箭头上的箭头

最后!!我最终不得不在jQuery命令之外定义整个变量,因为它在jquery href中的+符号一直存在问题.我使用以下代码来获得所需的结果.

    var i=0;

    % for p in row.photos:
     var photo='photo'+i;
     var photoId="#"+photo;
     var container='container'+i;
     var containerId="#"+container;
     var thumb='thumb'+i;
     var thumbId="#"+thumb;
       $('#photos').append("<div id="+photo+" class='thumbnailimage'></div>"); 
       $(photoId).append("<div id="+container+" class='thumb_container'></div>");  
       $(containerId).append("<div id="+thumb+" class='large_thumb'></div>");
       $(thumbId).append("<div class='large_thumb_border'></div>");   
       $(thumbId).append("<div class='large_thumb_shine'></div>");
       $(document.createElement("img")).attr({ "src": "${tg.url('photo/%s/%s' % (row.GISNUM, p.PHOTOINDEX))}" }).prependTo(thumbId);
% endfor

Answer 1

改变这个:

$('#photos').append("<div id='+i+' class='thumbnailimage'></div>"); 

至:

$('#photos').append("<div id='"+i+"' class='thumbnailimage'></div>"); 

请注意,如果页面的doctype不是HTML5,则ID必须以字母开头.

$('#photos').append("<div id='"+i+"' class='thumbnailimage'></div>"); 
$('#'+i).append("<div id='"+i+"container' class='thumb_container'></div>");  
$('#'+i+'container').append("<div id='"+i+"thumb' class='large_thumb'></div>");
$('#'+i+'thumb').append("<div class='large_thumb_border'></div>");
$('#'+i+'thumb').append("<div class='large_thumb_shine'></div>");