将stdout和stderr重定向到Function

Question

我需要帮助将输出(stdin和stdout)从系统命令发送到bash函数,同时仍然接受来自参数的输入.类似下面的例子.有人能指出我正确的道路吗？

LogMsg()
{
  DateTime=`date "+%Y/%m/%d %H:%M:%S"`
  echo '*****'$DateTime' ('$QMAKESPEC'): '$1 >> "$LogFile"
  echo $DateTime' ('$QMAKESPEC'): '$1
}

# Already works
LogMsg "This statement is sent directly"

# Wish I could do this:
# Capture both stdout & stderr of a system function to the logfile
# I do not presume that any of the syntax that follows is good
make 2>&1 >(LogMsg)

Answer 1

要做到这一点,你可以使用readbash内置:

LogMsg()
{
  read IN # This reads a string from stdin and stores it in a variable called IN
  DateTime=`date "+%Y/%m/%d %H:%M:%S"`
  echo '*****'$DateTime' ('$QMAKESPEC'): '$IN >> "$LogFile"
  echo $DateTime' ('$QMAKESPEC'): '$IN
}

然后使用管道:

make 2>&1 | LogMsg

更新:

为了能够使用stdin或参数作为输入(根据chepner的注释),您可以这样做:

LogMsg()
{
  if [ -n "$1" ]
  then
      IN="$1"
  else
      read IN # This reads a string from stdin and stores it in a variable called IN
  fi

  DateTime=`date "+%Y/%m/%d %H:%M:%S"`
  echo '*****'$DateTime' ('$QMAKESPEC'): '$IN >> "$LogFile"
  echo $DateTime' ('$QMAKESPEC'): '$IN
}

Answer 2

这是一个旧线程..但我用它来帮助我编写一个日志函数，该函数还将输出多行命令输出：

# Defines function to grab a time stamp #
get_Time () { Time=$(date +%Y-%m-%d\ %H:%M:%S) ; }

write_Log()
{
get_Time
if [ -n "${1}" ]; then         # If it's from a "<message>" then set it
    IN="${1}"
    echo "${Time} ${IN}" | tee -a ${log_File}
else
    while read IN               # If it is output from command then loop it
    do
        echo "${Time} ${IN}" | tee -a ${log_File}
    done
fi
}