python re.sub正则表达式

Question

Python不断返回一个字符损坏的字符串.

蟒蛇

test = re.sub('handle(.*?)', '<verse osisID="lol">\1</verse>', 'handle a bunch of random text here.')
print test

我想要的是

<verse osisID="lol">a bunch of random text here.</verse>

我得到了什么

<verse osisID="lol">*broken character*</verse>a bunch of random text here.

Answer 1

您应该转义\字符或使用r''原始字符串:

>>> re.sub('handle(.*?)', r'<verse osisID="lol">\1</verse>', 'handle a bunch of random text here.')
'<verse osisID="lol"></verse> a bunch of random text here.'

如果没有r''原始字符串文字,则反斜杠将被解释为转义码.你也可以加倍反斜杠:

>>> '\1'
'\x01'
>>> '\\1'
'\\1'
>>> r'\1'
'\\1'
>>> print r'\1'
\1

请注意,您只替换那里的单词handle,.*?模式至少匹配0个字符.删除问号,它将符合您的预期输出:

>>> re.sub('handle(.*)', r'<verse osisID="lol">\1</verse>', 'handle a bunch of random text here.')
'<verse osisID="lol"> a bunch of random text here.</verse>'