从OS X交叉编译到Linux

Question

我想从OS X 10.7 + Eclipse构建系统编译Linux服务器的二进制文件.这意味着GCC交叉编译器.我从本机4.7.1开始,为主机4.7.1射击.

大多数在线说明都特定于嵌入式开发.我想使用libstdc ++ - v3和glibc,这使它有点不同.

成功的是什么:

1. 安装包

   port install gcc47
   export CC=gcc-mp-47
   export LD=ld-mp-47
   export CXX=g++-mp-47
   export CPP=cpp-mp-47
   
   port install gmake
   ln /opt/local/bin/gmake /opt/local/bin/make
   
   port install gsed
   ln /opt/local/bin/gsed /opt/local/bin/sed
   
   port install gawk
   port install autoconf
   port install msgfmt
   

2. 制作并安装binutils-2.22

3. make all-gcc 和 make install-gcc

   使用以下配置:

   $ ../gcc/configure --enable-languages = c,c ++,objc,obj-c ++ --with-gmp =/opt/local --with-mpfr =/opt/local --with-mpc =/opt/local --prefix =/usr/local/cross/linux --target = x86_64-pc-linux-gnu --disable-nls

4. 将构建环境指向交叉编译器

   export CC=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-gcc
   export LD=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-ld
   export AR=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-ar
   export CXX=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-g++
   export CPP=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-cpp
   

5. 使用config构建glibc-2.16

   ../glibc/configure --host = x86_64-pc-linux-gnu --build = x86_64-apple-darwin11 --prefix =/usr/local/cross/linux/--with-binutils =/usr/local/cross/linux/bin/--with-headers =/usr/local/cross/linux/include/libc_cv_forced_unwind = yes libc_cv_ctors_header = yes libc_cv_c_cleanup = yes

失败:

glibc构建不久就失败了.此消息多次出现:

In file included from ./sysdeps/unix/sysdep.h:20:0,
                 from ./sysdeps/unix/x86_64/sysdep.h:18,
                 from sysdeps/unix/sysv/linux/x86_64/sysdep.h:22,
                 from <stdin>:1:
sysdeps/unix/sysv/linux/sys/syscall.h:24:24: fatal error: asm/unistd.h: No such file or directory
compilation terminated.

不过,这可能是正常的.

然后它无法生产stdio_lim.h.有了make -d,我明白了:

          Successfully remade target file `/Users/dkrauss/Documents/work/glibc-build/csu/abi-tag.h'.
          Considering target file `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h'.
           File `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h' does not exist.
           Looking for an implicit rule for `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h'.
           Trying pattern rule with stem `lim'.
           Trying implicit prerequisite `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.st'.
           Found an implicit rule for `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h'.
            Considering target file `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.st'.
            Recently tried and failed to update file `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.st'.
make[2]: *** No rule to make target `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.st', needed by `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h'.  Stop.

这是它试图构建的第一个头bits.有一个文件stdio_lim.h.in,它是.in其目录中唯一的文件.一些规则应该连接.st到.in？

Answer 1

为了正确构建 glibc，您需要来自 Linux 系统的头文件 - 可能内核头文件就足够了。

这是因为在该系统的软件的任何正常构建中都需要这些标头，并且在交叉编译时也没有什么不同。

我已经很长时间没有致力于创建交叉编译器了，所以我无法告诉你如何让 glibc 的构建看到头文件，但我相信它可以以直接的方式完成。