Android按钮背景选择器

Question

我想使用以下选择器作为按钮:

<selector xmlns:android="http://schemas.android.com/apk/res/android">

    <item android:drawable="@drawable/jobs" android:state_pressed="true">
        <shape android:shape="rectangle">
            <corners android:radius="5dp" />
        </shape>
<scale android:scaleHeight="90%" android:scaleWidth="90%" />
    </item>
    <item android:drawable="@drawable/jobs"></item>

</selector>

但它不起作用.我想让按钮角落圆形,尺寸小10%,同样的抽屉.实际上我想用单个drawable给按钮按下效果.可能吗？

Answer 1

我发现最好将状态逻辑和可绘制代码分开.来自Android文档:http://developer.android.com/guide/topics/resources/drawable-resource.html#StateList

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:state_pressed="true"
          android:drawable="@drawable/button_pressed" /> <!-- pressed -->
    <item android:state_focused="true"
          android:drawable="@drawable/button_focused" /> <!-- focused -->
    <item android:state_hovered="true"
          android:drawable="@drawable/button_focused" /> <!-- hovered -->
    <item android:drawable="@drawable/button_normal" /> <!-- default -->
</selector>

然后我会将代码放在一个单独的可绘制XML中给出圆角.我不确定你是否能直接做到这样的事情selector.