删除特殊字符前后的空格

Question

我有一个字符串,

String sample = "He won the International Rating Chess Tournament (IRCT ) which concluded on Dec. 22 at the Blue Sky Hotel , Canada";

我想删除字符')'和','之前留下的空格(如果有的话).所以最终输出应该是,

He won the International Rating Chess Tournament (IRCT) which concluded on Dec. 22 at the Blue Sky Hotel, Canada

谁能告诉我怎么做？

Answer 1

sample.replaceAll("\\s+(?=[),])", "");

即删除\s+紧跟(?=...)任何以下字符的所有空格[),].双反斜杠用于逃逸.有关正则表达式的更多信息,请参见此处:

http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html