阻止BASH评估变量中的文件名

Question

#!/bin/bash
#trash.sh

$TRASHDIR=$HOME/trash 
#Does not exist yet, i have loops further in 
#the script to check if the dir exists and to create it if not
echo $TRASHDIR
#I have ommited the rest of the script, 
#because this is where I have the problem

我们运行这个:

./trash.sh  
./trash.sh: line 3: =/home/someuser/trash: No such file or directory

如何在没有bash评估的情况下将此文件名存储在变量中？另外:我如何在以后的测试中使用此变量？

if [ -e $TRASHDIR ]
then
  echo stuff here
fi

Answer 1

定义 var $时,请先关闭初始字符:

TRASHDIR=$HOME/trash

当你使用时$TRASHDIR,将其bash评估为空字符串(或者先前设置的其他内容),这就是为什么它看起来像:

=/home/someuser/trash