如何在javascript函数中显示引导模式？

Question

我的页面上有一个按钮,当它被推送时会触发一些javascript函数发生,并且其中一个javascript函数可以打开一个bootstrap模式,但我似乎无法让它工作.这是我的代码......请帮忙.

 //elsewhere on the form is the button that triggers the javascript
  <a href="#" class="btn btn-danger" id="cancelPObtn" data-dismiss="modal">Yes, cancel it</a>

 <!-- CANCEL A PO MODAL -->
 <div class="modal hide fade" id="error-dialog" style="display: none;">
   <div class="modal-header">
        <a class="close" data-dismiss="modal">x</a>
        <h3>Cancel Purchase Order?</h3>
   </div>
   <div class="modal-body">
   </div>
   <div class="modal-footer">
       <a href="#" class="btn btn-danger btn-modal btn-cancel"  data-dismiss="modal">Yes, cancel it</a>
       <a href="#" class="btn" data-dismiss="modal">Nevermind</a>
   </div>
 </div>




      $('.btn-danger').click(function(event) {
          if(some random conditional statement){
             //some stuff happens here
          }
          else{ 
                //Show form validation error modal-- I know this part is triggered but the modal will not show
                $("#error-dialog").modal("show");
          }
      });

Answer 1

$( "#错误对话框")模式( "秀").

这是正确的方法,您的代码只是有错误.进入Chrome控制台并运行此命令即可.

Answer 2

你遗漏了if () {部分条件语句