Hur*_*rkS 3 iphone nsdictionary nsmutablearray ios
我正在尝试对NSDictionaries的mutableArray进行排序,目前我可以通过使用一个objectForKey值进行排序来实现这一点,但是这个问题是很多这些值可以是相同的所以我需要让另一个objectForKey来对数组进行排序.我想知道,如果第一个objectForKey比较返回一个相同的值,我怎么能进行第二个objectForKey比较,依此类推......
目前我正在这样做,这有效..但显然只有一个键.
[dataArrayOfDictionaries sortUsingComparator:^ NSComparisonResult(NSDictionary *d1, NSDictionary *d2)
{
NSString *n1 = [d1 objectForKey:@"DESCRIPTION"];
NSString *n2 = [d2 objectForKey:@"DESCRIPTION"];
return [n1 localizedCompare:n2];
} ];
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在我的调查中,我试过这个 -
[dataArrayOfDictionaries sortUsingComparator:^ NSComparisonResult(NSDictionary *d1, NSDictionary *d2)
{
NSString *n1 = [d1 objectForKey:@"DESCRIPTION"];
NSString *n2 = [d2 objectForKey:@"DESCRIPTION"];
return [n1 localizedCompare:n2];
n1 = [d1 objectForKey:@"ID"];
n2 = [d2 objectForKey:@"ID"];
return [n1 localizedCompare:n2];
} ];
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然而,这不起作用,因为它对描述排序然后完全使用基于ID,我想要它如果描述键是相同的然后通过ID键对这些值进行排序..如果这不起作用然后下去的列表键直到它排序..我希望这是有道理的..任何帮助将非常感激.
您几乎在问题中描述了解决方案:"如果描述键相同,则按ID键对这些值进行排序".您可以将该英语句子直接翻译成代码:
[dataArrayOfDictionaries sortUsingComparator:^ NSComparisonResult(NSDictionary *d1, NSDictionary *d2) {
NSString *n1 = [d1 objectForKey:@"DESCRIPTION"];
NSString *n2 = [d2 objectForKey:@"DESCRIPTION"];
NSComparisonResult result = [n1 localizedCompare:n2];
if (result == NSOrderedSame) {
n1 = [d1 objectForKey:@"ID"];
n2 = [d2 objectForKey:@"ID"];
result = [n1 localizedCompare:n2];
}
return result;
}];
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您还可以使用两个NSSortDescriptor对象执行排序:
[dataArrayOfDictionaries sortUsingDescriptors:[NSArray arrayWithObjects:
[NSSortDescriptor sortDescriptorWithKey:@"DESCRIPTION" ascending:YES
selector:@selector(localizedCompare:)],
[NSSortDescriptor sortDescriptorWithKey:@"ID" ascending:YES
selector:@selector(localizedCompare:)],
nil]];
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