如何在linux中查找包含字符串的行

Question

我在Linux中有一个文件,我想在该文件中显示包含特定字符串的行,该怎么做？

Answer 1

通常的方法是使用 grep

grep 'pattern' file

Answer 2

此外grep，您还可以使用其他实用程序，例如awk或sed

这里有几个例子。假设您要is在名为GPL.

您的示例文件

user@linux:~$ cat -n GPL 
     1    The GNU General Public License is a free, copyleft license for
     2    The licenses for most software and other practical works are designed
     3  the GNU General Public License is intended to guarantee your freedom to
     4  GNU General Public License for most of our software;
user@linux:~$ 

1.grep

user@linux:~$ grep is GPL 
  The GNU General Public License is a free, copyleft license for
the GNU General Public License is intended to guarantee your freedom to
user@linux:~$ 

2.awk

user@linux:~$ awk /is/ GPL 
  The GNU General Public License is a free, copyleft license for
the GNU General Public License is intended to guarantee your freedom to
user@linux:~$ 

3. sed

user@linux:~$ sed -n '/is/p' GPL
  The GNU General Public License is a free, copyleft license for
the GNU General Public License is intended to guarantee your freedom to
user@linux:~$ 

希望这可以帮助

Answer 3

/ tmp / myfile

first line text
wanted text
other text

命令

$ grep -n "wanted text" /tmp/myfile | awk -F  ":" '{print $1}'
2

Answer 4

所述的grep命令的家族(包括egrep的,fgrep一样)是用于这个通常的解决方法.

$ grep pattern filename

如果您正在搜索源代码,那么ack可能是更好的选择.它将自动搜索子目录并避免您通常不搜索的文件(对象,SCM目录等)