Chr*_*ris 63 xcode objective-c uipickerview ios swift
我的UIPickerView有问题.我在EU AP和NA中有3个值.当我启动应用程序欧盟似乎被选中但是当我做一个NSLog(@"%@", [regions objectAtIndex:row]);我只回来时(null),现在当我触摸UIPickerView时,选择了EU值并且我"EU"从NSLog返回.
我的问题是:
当用户仅启动应用程序并且什么都不触摸时,如何定义所选的默认值(不仅是标签).
编辑:这是我获取所选项目的代码:
#pragma mark -
#pragma mark PickerView DataSource
- (NSInteger)numberOfComponentsInPickerView:
(UIPickerView *)pickerView
{
return 1;
}
- (NSInteger)pickerView:(UIPickerView *)pickerView
numberOfRowsInComponent:(NSInteger)component
{
return [regions count];
}
- (NSString *)pickerView:(UIPickerView *)pickerView
titleForRow:(NSInteger)row
forComponent:(NSInteger)component
{
return [regions objectAtIndex:row];
}
#pragma mark -
#pragma mark PickerView Delegate
-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row
inComponent:(NSInteger)component
{
selectedRegion = [[NSString alloc] initWithFormat:
@"%@", [regions objectAtIndex:row]];
NSLog(@"%@", selectedRegion);
}
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Tot*_*mus 93
TL:DR版本:
//Objective-C
[self.picker selectRow:2 inComponent:0 animated:YES];
//Swift
picker.selectRow(2, inComponent:0, animated:true)
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要么你没有设置你的选择器来选择行(你说你似乎已经做过但无论如何):
- (void)selectRow:(NSInteger)row inComponent:(NSInteger)component animated:(BOOL)animated
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或者您没有使用以下方法从选择器中获取所选项目
- (NSInteger)selectedRowInComponent:(NSInteger)component
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这将从您的选择器中将所选行作为整数获取,并随意使用它.这应该为你做的伎俩.祝好运.
无论如何阅读参考:https: //developer.apple.com/documentation/uikit/uipickerview
编辑:
在UIPickerView中手动设置和获取所选行的示例:
.h文件:
#import <UIKit/UIKit.h>
@interface ViewController : UIViewController <UIPickerViewDelegate, UIPickerViewDataSource>
{
UIPickerView *picker;
NSMutableArray *source;
}
@property (nonatomic,retain) UIPickerView *picker;
@property (nonatomic,retain) NSMutableArray *source;
-(void)pressed;
@end
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.m文件:
#import "ViewController.h"
@interface ViewController ()
@end
@implementation ViewController
@synthesize picker;
@synthesize source;
- (void)viewDidLoad
{
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
}
- (void)viewDidUnload
{
[super viewDidUnload];
// Release any retained subviews of the main view.
}
- (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation
{
return YES;
}
- (void) viewWillAppear:(BOOL)animated
{
[super viewWillAppear:animated];
self.view.backgroundColor = [UIColor yellowColor];
self.source = [[NSMutableArray alloc] initWithObjects:@"EU", @"USA", @"ASIA", nil];
UIButton *pressme = [[UIButton alloc] initWithFrame:CGRectMake(20, 20, 280, 80)];
[pressme setTitle:@"Press me!!!" forState:UIControlStateNormal];
pressme.backgroundColor = [UIColor lightGrayColor];
[pressme addTarget:self action:@selector(pressed) forControlEvents:UIControlEventTouchUpInside];
[self.view addSubview:pressme];
self.picker = [[UIPickerView alloc] initWithFrame:CGRectMake(20, 110, 280, 300)];
self.picker.delegate = self;
self.picker.dataSource = self;
[self.view addSubview:self.picker];
//This is how you manually SET(!!) a selection!
[self.picker selectRow:2 inComponent:0 animated:YES];
}
//logs the current selection of the picker manually
-(void)pressed
{
//This is how you manually GET(!!) a selection
int row = [self.picker selectedRowInComponent:0];
NSLog(@"%@", [source objectAtIndex:row]);
}
- (NSInteger)numberOfComponentsInPickerView:
(UIPickerView *)pickerView
{
return 1;
}
- (NSInteger)pickerView:(UIPickerView *)pickerView
numberOfRowsInComponent:(NSInteger)component
{
return [source count];
}
- (NSString *)pickerView:(UIPickerView *)pickerView
titleForRow:(NSInteger)row
forComponent:(NSInteger)component
{
return [source objectAtIndex:row];
}
#pragma mark -
#pragma mark PickerView Delegate
-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row
inComponent:(NSInteger)component
{
// NSLog(@"%@", [source objectAtIndex:row]);
}
@end
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编辑Swift解决方案(来源:Dan Beaulieu的回答)
定义出口:
@IBOutlet weak var pickerView: UIPickerView! // for example
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然后在viewWillAppear或viewDidLoad中,您可以使用以下内容:
pickerView.selectRow(rowMin, inComponent: 0, animated: true)
pickerView.selectRow(rowSec, inComponent: 1, animated: true)
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如果你检查Swift 2.0框架,你会看到.selectRow定义为:
func selectRow(row: Int, inComponent component: Int, animated: Bool)
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选项单击 .selectRow在Xcode中显示以下内容:
Har*_*rji 18
这是如何设置UIPickerView的默认值
[self.picker selectRow:4 inComponent:0 animated:YES];
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定义出口:
@IBOutlet weak var pickerView: UIPickerView! // for example
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然后在viewWillAppear或viewDidLoad中,您可以使用以下内容:
pickerView.selectRow(rowMin, inComponent: 0, animated: true)
pickerView.selectRow(rowSec, inComponent: 1, animated: true)
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如果您检查Swift 2.0框架,您将看到.selectRow定义为:
func selectRow(row: Int, inComponent component: Int, animated: Bool)
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选项单击 .selectRow在Xcode中显示以下内容:

小智 6
我也有这个问题.但显然存在方法调用顺序的问题.你必须打电话:
[self.picker selectRow:2 inComponent:0 animated:YES];
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打电话后
[self.view addSubview:self.picker];
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您必须
- (void)selectRow:(NSInteger)row inComponent:(NSInteger)component animated:(BOOL)animated
在它出现之前发送到选取器视图。文档指出方法 selectedRowInComp... 将给出 -1,因此选取器视图可能处于没有选定行的状态。事实证明,它在创建时就处于这种状态。
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